Evaluate "xp- a. Start with the substitution u = e* and note that u² = e*, This should lead to the integral [ -du. b. Next use a trig. substitution u = (trig. function of 0) (You will end up with a sin 20. To convert back to u and then x you can use sin(28) = 2sin@ cos0.)
Evaluate "xp- a. Start with the substitution u = e* and note that u² = e*, This should lead to the integral [ -du. b. Next use a trig. substitution u = (trig. function of 0) (You will end up with a sin 20. To convert back to u and then x you can use sin(28) = 2sin@ cos0.)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Evaluate the integral**
\[ \int \frac{e^x}{1-e^{2x}}\, dx. \]
### Steps to Approach the Integral
**a. Start with the substitution**
\[ u = e^x \]
and note that
\[ u^2 = e^{2x}. \]
This should lead to the integral
\[ \int \frac{u}{1-u^2}\, du. \]
**b. Next, use a trigonometric substitution**
\[ u = \text{(trig. function of } \theta \text{)} \]
---
*(At this point, you will end up with a \(\sin{2\theta}\). To convert back to \(u\) and then \(x\), you can use \(\sin{(2\theta)} = 2\sin{\theta}\cos{\theta}\)).*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F26d30d07-cf68-433f-ae62-11ba4edb12d8%2Fe558a3d2-af36-4bb4-8793-9e9ee37af722%2Fs6thq58.png&w=3840&q=75)
Transcribed Image Text:**Evaluate the integral**
\[ \int \frac{e^x}{1-e^{2x}}\, dx. \]
### Steps to Approach the Integral
**a. Start with the substitution**
\[ u = e^x \]
and note that
\[ u^2 = e^{2x}. \]
This should lead to the integral
\[ \int \frac{u}{1-u^2}\, du. \]
**b. Next, use a trigonometric substitution**
\[ u = \text{(trig. function of } \theta \text{)} \]
---
*(At this point, you will end up with a \(\sin{2\theta}\). To convert back to \(u\) and then \(x\), you can use \(\sin{(2\theta)} = 2\sin{\theta}\cos{\theta}\)).*
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