Using the standard reduction potentials in Table 2, calculate the equilibrium constant at 25℃ for the reaction Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)
Using the standard reduction potentials in Table 2, calculate the equilibrium constant at 25℃ for the reaction Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the standard reduction potentials in Table 2, calculate the equilibrium constant at
25℃ for the reaction
Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)

Transcribed Image Text:Table 2. Standard Reduction Potentials at 25 °C.
Half-Reaction
E'(V)
Ftg) + 2e
O,(g) + 2H"(aq) + 2e
Co"(ag) +e
H,O,(aq) + 2H' (aq) + 2e
PhO,(8) + 4H'(aq) - so; (aq) + 2e
Ce**(aq) + e Ce*tag)
MnO, (aq) + 8H (aq) + Se
Au"(ag) + 3e Au(x)
Cl:(g) + 2e
Cr,0, (aq) + 14H (aq) + 6e
MnO,(s) + 4H'(aq) + 2e
0,(g) + 4H'(aq) + 4e
Bry(l)
→ 2F (aq)
+2.87
Og) + H,0
+ Co "(aq)
+2.07
+1.82
+ 2H,0
+1.77
PHSO,(s) 2H,0
+1.70
+1.61
Mn"(aq) + 4H,0
+1.51
+1.50
2CI (aq)
+1.36
2Cr* (aq) + 7H,0
Mn (aq) + 2H,0
2H,0
+1.33
+1.23
+1.23
+ 2e 2Br (ag)
+1.07
+ 4H (ag) + 3e
→ Hg"(aq)
NO, (aq)
2Hg (aq) + 2e
Hg" (aq) + 2e - 2Hg(l)
Ag (aq) + e
Fe" (aq) + e Fe* (aq)
Og) + 2H (ag) - 2e
MnO, (aq)
L(s) + 2e
O(g) + 2H,0 + 4e 40H (ag)
Cu" (aq) + 2e
AgCs) + e
so, (aq) + 4H (aq) + 2e SO:(g) + 2H,0
Cu"(aq)
So" (aq) + 2e → Sn taq)
21*(aq)
Ph" (aq) + 2e
Sn"(aq) + 2e
Ni" (aq) + 2e
Co"(aq) + 2e Cols)
PHSO,(s) + 2e
Cơ (aq)
Fe" (aq)
C*taq)
Zn" (aq)
2H,0 + 2e
Mn* (aq) + 2e
AP (aq) + 3e
Be" (ag) + 2e
Mg"(aq) + 2e Mg(s)
Na (aq) + e
Ca" (aq)
Sr*(aq) + 2e Sris)
Ba"(ag)
K'(aq) +e
Li"(ag) +e - Lits)
NO(g) + 2H,0
+0.96
+0.92
+0.85
+ Ag(s)
+0.80
+0,77
- H,O,(aq)
+0.68
+ 2H,0 + 3e MnO,fs) + 40H (aq)
21 lag)
+0.59
+0.53
+0.40
+ Cu(s)
+0.34
- Agts) + CI (aq)
+0.22
+0.20
+e Cu (aq)
+0.15
+0.13
2e
0.00
+ Ph(s)
+ Sn(s)
- Nits)
-0,13
-0.14
-0.25
-0.28
Ph(s) + so (aq)
- Cd(s)
+ Fels)
-0.31
+ 2e
+ 2e
-0.40
--0.44
+ 3e
Cris)
-0,74
+ Znts)
(bv) HOT + (8FH-
+ Mn(s)
+ Als)
+ Be(s)
+ 2e
-0.76
-0,83
-1.18
-1.66
-1.85
-2.37
-2.71
-2.87
+ Na(s)
+ 2e
Ca(s)
-2,89
2e
Ba(s)
-2.90
-2.93
Kis)
-3.05
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