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Using the standard reduction potentials in Table 2, calculate the equilibrium constant at 25℃ for the reaction Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)

Using the standard reduction potentials in Table 2, calculate the equilibrium constant at 25℃ for the reaction Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the standard reduction potentials in Table 2, calculate the equilibrium constant at
25℃ for the reaction
Br2(l) + 2Cl-(aq) ---> Cl2(g) + 2 Br-(aq)

 

Table 2. Standard Reduction Potentials at 25 °C. Half-Reaction E'(V) Ftg) + 2e O,(g) + 2H"(aq) + 2e Co"(ag) +e H,O,(aq) + 2H' (aq) + 2e PhO,(8) + 4H'(aq) - so; (aq) + 2e Ce**(aq) + e Ce*tag) MnO, (aq) + 8H (aq) + Se Au"(ag) + 3e Au(x) Cl:(g) + 2e Cr,0, (aq) + 14H (aq) + 6e MnO,(s) + 4H'(aq) + 2e 0,(g) + 4H'(aq) + 4e Bry(l) → 2F (aq) +2.87 Og) + H,0 + Co "(aq) +2.07 +1.82 + 2H,0 +1.77 PHSO,(s) 2H,0 +1.70 +1.61 Mn"(aq) + 4H,0 +1.51 +1.50 2CI (aq) +1.36 2Cr* (aq) + 7H,0 Mn (aq) + 2H,0 2H,0 +1.33 +1.23 +1.23 + 2e 2Br (ag) +1.07 + 4H (ag) + 3e → Hg"(aq) NO, (aq) 2Hg (aq) + 2e Hg" (aq) + 2e - 2Hg(l) Ag (aq) + e Fe" (aq) + e Fe* (aq) Og) + 2H (ag) - 2e MnO, (aq) L(s) + 2e O(g) + 2H,0 + 4e 40H (ag) Cu" (aq) + 2e AgCs) + e so, (aq) + 4H (aq) + 2e SO:(g) + 2H,0 Cu"(aq) So" (aq) + 2e → Sn taq) 21*(aq) Ph" (aq) + 2e Sn"(aq) + 2e Ni" (aq) + 2e Co"(aq) + 2e Cols) PHSO,(s) + 2e Cơ (aq) Fe" (aq) C*taq) Zn" (aq) 2H,0 + 2e Mn* (aq) + 2e AP (aq) + 3e Be" (ag) + 2e Mg"(aq) + 2e Mg(s) Na (aq) + e Ca" (aq) Sr*(aq) + 2e Sris) Ba"(ag) K'(aq) +e Li"(ag) +e - Lits) NO(g) + 2H,0 +0.96 +0.92 +0.85 + Ag(s) +0.80 +0,77 - H,O,(aq) +0.68 + 2H,0 + 3e MnO,fs) + 40H (aq) 21 lag) +0.59 +0.53 +0.40 + Cu(s) +0.34 - Agts) + CI (aq) +0.22 +0.20 +e Cu (aq) +0.15 +0.13 2e 0.00 + Ph(s) + Sn(s) - Nits) -0,13 -0.14 -0.25 -0.28 Ph(s) + so (aq) - Cd(s) + Fels) -0.31 + 2e + 2e -0.40 --0.44 + 3e Cris) -0,74 + Znts) (bv) HOT + (8FH- + Mn(s) + Als) + Be(s) + 2e -0.76 -0,83 -1.18 -1.66 -1.85 -2.37 -2.71 -2.87 + Na(s) + 2e Ca(s) -2,89 2e Ba(s) -2.90 -2.93 Kis) -3.05
Transcribed Image Text:Table 2. Standard Reduction Potentials at 25 °C. Half-Reaction E'(V) Ftg) + 2e O,(g) + 2H"(aq) + 2e Co"(ag) +e H,O,(aq) + 2H' (aq) + 2e PhO,(8) + 4H'(aq) - so; (aq) + 2e Ce**(aq) + e Ce*tag) MnO, (aq) + 8H (aq) + Se Au"(ag) + 3e Au(x) Cl:(g) + 2e Cr,0, (aq) + 14H (aq) + 6e MnO,(s) + 4H'(aq) + 2e 0,(g) + 4H'(aq) + 4e Bry(l) → 2F (aq) +2.87 Og) + H,0 + Co "(aq) +2.07 +1.82 + 2H,0 +1.77 PHSO,(s) 2H,0 +1.70 +1.61 Mn"(aq) + 4H,0 +1.51 +1.50 2CI (aq) +1.36 2Cr* (aq) + 7H,0 Mn (aq) + 2H,0 2H,0 +1.33 +1.23 +1.23 + 2e 2Br (ag) +1.07 + 4H (ag) + 3e → Hg"(aq) NO, (aq) 2Hg (aq) + 2e Hg" (aq) + 2e - 2Hg(l) Ag (aq) + e Fe" (aq) + e Fe* (aq) Og) + 2H (ag) - 2e MnO, (aq) L(s) + 2e O(g) + 2H,0 + 4e 40H (ag) Cu" (aq) + 2e AgCs) + e so, (aq) + 4H (aq) + 2e SO:(g) + 2H,0 Cu"(aq) So" (aq) + 2e → Sn taq) 21*(aq) Ph" (aq) + 2e Sn"(aq) + 2e Ni" (aq) + 2e Co"(aq) + 2e Cols) PHSO,(s) + 2e Cơ (aq) Fe" (aq) C*taq) Zn" (aq) 2H,0 + 2e Mn* (aq) + 2e AP (aq) + 3e Be" (ag) + 2e Mg"(aq) + 2e Mg(s) Na (aq) + e Ca" (aq) Sr*(aq) + 2e Sris) Ba"(ag) K'(aq) +e Li"(ag) +e - Lits) NO(g) + 2H,0 +0.96 +0.92 +0.85 + Ag(s) +0.80 +0,77 - H,O,(aq) +0.68 + 2H,0 + 3e MnO,fs) + 40H (aq) 21 lag) +0.59 +0.53 +0.40 + Cu(s) +0.34 - Agts) + CI (aq) +0.22 +0.20 +e Cu (aq) +0.15 +0.13 2e 0.00 + Ph(s) + Sn(s) - Nits) -0,13 -0.14 -0.25 -0.28 Ph(s) + so (aq) - Cd(s) + Fels) -0.31 + 2e + 2e -0.40 --0.44 + 3e Cris) -0,74 + Znts) (bv) HOT + (8FH- + Mn(s) + Als) + Be(s) + 2e -0.76 -0,83 -1.18 -1.66 -1.85 -2.37 -2.71 -2.87 + Na(s) + 2e Ca(s) -2,89 2e Ba(s) -2.90 -2.93 Kis) -3.05
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