Using the normal approximation for the binomial distribution, what is the test statistic for this sample þased on the sample proportion? = 21 (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the p-value for this sample. p-value = (Report answer as a decimal accurate to 4 decimal places.) This p-value (and test statistic) leads to a decision to... O reject the null hypothesis O accept the null hypothesis O fail to reject the null hypothesis reject the alternative hypothesis As such, the final conclusion is that... O There is enough evidence to show that there is not a different proportion of only children in the G&T program. O There is not enough evidence to show that there is not a different proportion of only children in the G&T program. O There is enough evidence to show that there is a different proportion of only children in the G&T program. OThere is not enough evidence to show that there is a different proportion of only children in the G&T program.

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In a certain school district, it was observed that 32% of the students in the element schools were classified
as only children (no siblings). However, in the special program for talented and gifted children, 164 out of
432 students are only children. The school district administrators want to know if the proportion of only
children in the special program is different from the proportion for the school district. Test at the
¤3D0.02 level of significance.
What is the hypothesized population proportion for this test?
(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)
Based on the statement of this problem, how many tails would this hypothesis test have?
O one-tailed test
Otwo-tailed test
Choose the correct pair of hypotheses for this situation:
(A)
(B)
(C)
H:p = 0.32 | Ho:p= 0.32
Ho:p = 0.32
=0,32
%3D
Ha:p<0.32 Ha:p 0.32 H:p> 0.32
(D)
|(E)
(F)
Но : р - 0.38| Но: р — 0.38 Но: р - 0.38
Ho:p 0.38
HaP
0.38 H:p 0.38 H:p> 0.38
(A) (B) (C) (D) (E) (F)
Transcribed Image Text:In a certain school district, it was observed that 32% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 164 out of 432 students are only children. The school district administrators want to know if the proportion of only children in the special program is different from the proportion for the school district. Test at the ¤3D0.02 level of significance. What is the hypothesized population proportion for this test? (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? O one-tailed test Otwo-tailed test Choose the correct pair of hypotheses for this situation: (A) (B) (C) H:p = 0.32 | Ho:p= 0.32 Ho:p = 0.32 =0,32 %3D Ha:p<0.32 Ha:p 0.32 H:p> 0.32 (D) |(E) (F) Но : р - 0.38| Но: р — 0.38 Но: р - 0.38 Ho:p 0.38 HaP 0.38 H:p 0.38 H:p> 0.38 (A) (B) (C) (D) (E) (F)
Using the normal approximation for the binomial distribution, what is the test statistic for this sample
pased on the sample proportion?
(Report answer as a decimal accurate to 3 decimal places.)
You are now ready to calculate the p-value for this sample.
p-value =
(Report answer as a decimal accurate to 4 decimal places.)
This p-value (and test statistic) leads to a decision to...
O reject the null hypothesis
O accept the null hypothesis
O fail to reject the null hypothesis
O reject the alternative hypothesis
As such, the final conclusion is that...
O There is enough evidence to show that there is not a different proportion of only children in the G&T
program.
O There is not enough evidence to show that there is not a different proportion of only children in the
G&T program.
O There is enough evidence to show that there is a different proportion of only children in the G&T
program.
There is not enough evidence to show that there is a different proportion of only children in the G&T
program.
Transcribed Image Text:Using the normal approximation for the binomial distribution, what is the test statistic for this sample pased on the sample proportion? (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the p-value for this sample. p-value = (Report answer as a decimal accurate to 4 decimal places.) This p-value (and test statistic) leads to a decision to... O reject the null hypothesis O accept the null hypothesis O fail to reject the null hypothesis O reject the alternative hypothesis As such, the final conclusion is that... O There is enough evidence to show that there is not a different proportion of only children in the G&T program. O There is not enough evidence to show that there is not a different proportion of only children in the G&T program. O There is enough evidence to show that there is a different proportion of only children in the G&T program. There is not enough evidence to show that there is a different proportion of only children in the G&T program.
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