Using the Nernst equation calculate the cell voltage for: Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) when the [Fe2+] = 0.14 M and [Cd2+] = 1.6 M. Potentially useful information: Fe2+ + 2e− → Fe(s); ε0 = -0.44 VCd2+ + 2e− → Cd(s); ε0 = -0.40 V
Using the Nernst equation calculate the cell voltage for: Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) when the [Fe2+] = 0.14 M and [Cd2+] = 1.6 M. Potentially useful information: Fe2+ + 2e− → Fe(s); ε0 = -0.44 VCd2+ + 2e− → Cd(s); ε0 = -0.40 V
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.95QE
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Question
Using the Nernst equation calculate the cell voltage for:
Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s)
when the [Fe2+] = 0.14 M and [Cd2+] = 1.6 M.
Potentially useful information:
Fe2+ + 2e− → Fe(s); ε0 = -0.44 V
Cd2+ + 2e− → Cd(s); ε0 = -0.40 V
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