using the molar heat of neutralization of solution = -53760 kj/ mol HCI calculate how much heat you would expect to be produced if you mixed 50.0mL of 0.250M HCI with by 50.0mL of 0.250M NaOH ( hint how many moles of HCI are involved)

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A:

Q: How many mL of 0.300 M HCI would be needed to just neutralize 20.0 mL of 0.250 M NaOH?

A:

Q: How many mL of water must be added to 300.0 mL of 0.750 M HCl to dilute the solution to 0.25 M?

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Q: If 8.00 mL of a different hydrochloric acid solution had a known concentration of 0.3456 M, how many…

A: Volume of HCl  solution (V1)  = 8.00 mL = 0.008 L  (1 mL = 0.001 L)  Concentration of  HCl solution…

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A: Applying formula M1V1= M2V2

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A: Hey, since you have asked multiple question, we will solve the first question for you. If you want…

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A: Given-> Volume of KOH = 2.37L Molarity of KOH = 1.30 mole/L

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A: M1V1 = M2V2

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A: Acid-base neutralization: During acid-base titration, the neutralization is achieved when an equal…

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A: Answer:Reaction between KHP and NaOH is shown below:According to reaction stoichiometry, 1 mole of…

Q: How many milliliters of 0.250M HCl solution will exactly react with 10.5g of of solid NaHCO3?

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Q: If 5.00 mL of HCl requires 4.96 mL of 0.9581 M NaOH to consume the HCl, what is the concentration of…

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A: Given  Volume of HCl     = 100 mL                              = 0.1 Liter                    ( 1 mL…

Q: How many mls of .1 M NaOH would be needed to react with 20 mls of .05 M H3PO4 in the neutralization…

A: The reaction taking place will be  3 NaOH + H3PO4 ----> Na3PO4 + 3 H2O  Hence from the above…

Q: You will be creating a 100.00 mL of a 1.00 M HCl solution from a 5.00 M solution. Explain in detail…

A: The equation for dilution is given below.M1V1 = M2V2

Q: How much water should be added to 25.0 mL of 0.227 M HCl to dilute the solution to0.105 M?

A:

Q: alnze 20.5 mL of the acid. type your answer.. Previous

A: Applying formula of molarity M1V1=  M2V2

Q: You need 50 millilitres of a HCL solution that is 0.02N. You have on hand 0.5N solution. How would…

A:

Q: If 8.00 mL of a different hydrochloric acid solution had a known concentration of 0.3456 M, how many…

A: The equivalence point or stoichiometric point is the point in a chemical reaction when there is…

Q: f 8.00 mL of a different hydrochloric acid solution had a known concentration of 0.3456 M, how many…

A: Solution-   Volume of HCL, V1 = 8.0 mL Molarity of HCI, M1 = 0.3456M Volume of NaOH, V2 = ?

Q: At the equivalence point, you had equal number of moles of acid and base, and the acid was…

A: The required calculations have been done in the following step.

Q: How many moles of HCl are needed to completely react with 50.0 mL of 0.250 M NaOH solution?

A: It is given that:Molarity of NaOH solution = 0.250 MVolume of solution = 50.0 mL

Q: Calculate the concentration in (M) of the unknown NaOH solution in the fourth case. NaOH volume (mL)…

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Q: A 40.0 mL solution of KOH is neutralized with 31.3 mL of 0.300 M HCl. What is the concentration of…

A:

Q: concentration of the acid

A:

Q: Calculate the concentration of sodium hydroxide from the following data. Record your answer in…

A: Given, mass of potassium hydrogen phthalate = 0.514 g volume of NaOH = 22.79 mL

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Q: If 8.00 mL of a different hydrochloric acid solution had a known concentration of 0.3456 M, how many…

A: Use simply  M1V1 = M2V2

Q: How do you caclulate the water added?

A: It is given that initially we had the 25 mL of solution. Then we added the water to the solution so…