15. How many mL of 2.00 M sodium hydroxide are needed to neutralize 50.0 mL of 10.0 M sulfuric acid?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question 15**:
How many mL of 2.00 M sodium hydroxide are needed to neutralize 50.0 mL of 10.0 M sulfuric acid?

For educational purposes, remember that neutralization involves a reaction between an acid and a base, often producing water and a salt. In this case, the key is to understand the stoichiometry of the reaction between sulfuric acid (\( \text{H}_2\text{SO}_4 \)) and sodium hydroxide (\( \text{NaOH} \)), which is:

\[ \text{H}_2\text{SO}_4 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{SO}_4 + 2 \text{H}_2\text{O} \]

This reaction shows that one mole of sulfuric acid requires two moles of sodium hydroxide for complete neutralization.
Transcribed Image Text:**Question 15**: How many mL of 2.00 M sodium hydroxide are needed to neutralize 50.0 mL of 10.0 M sulfuric acid? For educational purposes, remember that neutralization involves a reaction between an acid and a base, often producing water and a salt. In this case, the key is to understand the stoichiometry of the reaction between sulfuric acid (\( \text{H}_2\text{SO}_4 \)) and sodium hydroxide (\( \text{NaOH} \)), which is: \[ \text{H}_2\text{SO}_4 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{SO}_4 + 2 \text{H}_2\text{O} \] This reaction shows that one mole of sulfuric acid requires two moles of sodium hydroxide for complete neutralization.
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