A 0.1310 g sample of an unknown diprotic acid is diluted to 100.00 mL and titrated by using 0.1910 M NaOH. If 14.20 mL of the NaOH solution is required to reach the second equivalence point, what is the molar mass of the acid? 2.

Q: An analytical chemist weighs out 0.203 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: The point that appears in the titration curve, where the number of moles of an acid and the number…

Q: A 0.75 L sample of aqueous Ca(OH)2 is titrated with a 0.384 M HCl solution and 0.89 L are required…

A: The chemical reaction taking place during titration is shown below, Observing the balanced reaction…

Q: A 0.392 g sample of a monoprotic acid is dissolved in water and titrated with 0.120 M KOH. What is…

A: We have to calculate the molar mass of acid.

Q: An analytical chemist weighs out 0.165 g of an unknown triprotic acid into a 250 mL volumetric flask…

A: The unknown acid is triprotoic acid, hence the balanced chemical reaction between the acid and NaOH…

Q: A titration required 22.30 mL of 2.567 M Sr(OH)2 to neutralize 6.50 g of an unknown diprotic acid.…

A: For Sr(OH)2 solution,Concentration of Sr(OH)2 solution = 2.567 M = 2.567 mol/LVolume of Sr(OH)2…

Q: A 1.146 g sample of weak acid is dissolved in 164.2 mL of water and titrated with 0.248 M NaOH to…

A: Given, mass of weak acid = 1.146 g Volume of weak acid = 164.2 mL Concentration of NaOH = 0.248 M…

Q: An analytical chemist weighs out 0.244 g of an unknown diprotic acid into a 250 mL volumetric flask…

A:

Q: An analytical chemist weighs out 0.099 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: The point in the titration curve, where the moles of acid and the moles of the base are equal in…

Q: An analytical chemist weighs out 0.102 g of an unknown diprotic acid into a 250 mL volumetric flask…

A:

Q: In a titration, 33.1 mL of 0.82 M KOH were needed to neutralize 25.0 mL of HCl. How many moles of…

A: The objective of this question is to determine the number of moles of HCl present in the solution…

Q: A solution of oxalic acid is used to titrate 17.11 mL of a 0.5003 molar: sodium hydroxide. If the…

A:

Q: An analytical chemist weighs out 0.461 g of an unknown triprotic acid into a 250 mL volumetric flask…

A: The molar mass of an unknown acid is to be calculated from the given data. Given: Mass of unknown…

Q: The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains…

A:

Q: The titration of 25.00 mL of a sulphuric acid solution of an unknown concentration requires 31.22 mL…

A: The reaction in which an acid and a base react to produce salt and water is called as…

Q: An analytical chemist weighs out  0.149g  of an unknown diprotic acid into a  250mL  volumetric…

A: Answer:- This question is answered by using the simple concept of stoichiometry using balanced…

Q: A titration of a 25.00 mL sample of a hydrochloric acid solution of unknown molarity reaches the…

A: The equivalence point in acid base solution is  Moles of acid = Moles of base

Q: A 1.25g sample of impure sodium carbonate requires 18.20 mL of 0.480 M HCL to become completely…

A: Molarity is defined as the concentration of the given solution which can be expressed as the ratio…

Q: A 16.24 mL sample of dilute H3PO4 requires 40.52 of 0.108 M NaOH for complete neutralization.…

A: The reaction taking place is  3 NaOH + H3PO4 ----> Na3PO4 + 3 H2O Hence from the above reaction…

Q: If 2.001 g KHP is titrated with 16.50 mL of NAOH what is the concentration of NAOH?

A: Note: KHP: potassium hydrogen phthlate (KHC8H4O4)KHP + NaOH ----> NaKP + H2Omass of KHP = 2.001…

Q: A 13.8 mL solution of 0.176 M phosphoric acid (aq) is to be titrated with 0.384 M sodium hydroxide…

A: The mathematical calculation can be explained using acidimetry and alkalimetry . From this principle…

Q: You have a solution of NaOH of unknown concentration.  A 15.98 mL sample of the NaOH solution was…

A: Concentration of NaOH = To be determined Volume of NaOH = 15.98 mLMolarity of HNO3 = 0.377 MVolume…

Q: An analytical chemist weighs out 0.278 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: Given-> Weight of diprotic acid = 0.278 gm Volume of flask= 250 ml = 0.250 L (1 L = 1000 ml)…

Q: n an experiment, a 500.0 mL solution of approximately 0.250 M KOH (56.106 g/mol) solution was…

A:

Q: A 0.307-g sample of an unknown triprotic acid is titrated completely using 35.2 mL of 0.106 M NaOH.…

A:

Q: Titrations are generally both more accurate and more precise the smaller the concentration of…

A:

Q: A 0.760 g sample of a diprotic acid is dissolved in water and titrated with  M NaOH.0.260 M NaOH.…

A: Assuming the diprotic acid has formula H2A hence the reaction will be  H2A + 2 NaOH ----> 2 NaA +…

Q: An analytical chemist weighs out 0.406 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: The point in the titration curve, where the moles of acid and the moles of the base are equal in…

Q: 50.00 mL of an acetic acid solution is titrated with 0.1000 M NaOH. 23.90 mL NaOH is required to…

A: Given : Volume of acetic acid = 50 ml Volume of NaOH = 23.90 ml Molarity of NaOH = 0.1000M

Q: An analytical chemist weighs out 0.203 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: l

Q: An analytical chemist weighs out 0.275 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: Answer:Number of moles of any specie in a solution is always equal to the product of molar…

Q: A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make…

A: The relation between normality (N) and molarity (M) is shown below where v is the valency of the…

Q: A 33.2 mL sample of a 0.499 M aqueous acetic acid solution is titrated with a 0.291 M aqueous…

A: Given volume of acetic acid is 33.2 molecule and strength is 0.499 M.It is titrated against 0.291 M…

Q: Chromic acid, H2CrO4, is used in ceramic glazes and colored glass, and is particularly effective for…

A: Answer:- This question is answered by using the simple concept of stoichiometry which involves the…

Q: In a titration experiment, a solution of rubidium hydroxide (RBOH) of unknown concentration was…

A:

Q: An analytical chemist weighs out 0.279 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: The given data contains, mass = 0.279 g. Volume = 250 ml. Molarity of NaOH=0.1400 M. Volume of NaOH…

Q: A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make…

A: Given, Normality=n×molarityConcentration of NaOH,n-factor=1 for sodium hydroxideN1=1×0.750 =0.750…

Q: A 25.0 mL volume of HCI solution of unknown concentration is titrated with a 0.178 M NaOH solution.…

A: Volume of HCl solution,V1 = 25 mL Volume of NaOH solution,V2 = 16.6 mL Concentration of NaOH…

Q: An analytical chemist weighs out 0.311 g of an unknown diprotic acid into a 250 mL volumetric flask…

A:

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.