using the launch velocity determined in question 1 or 2 (should be the same!) determine the maximum range of the rocket, with a launch angle of 45 degrees.  *Assume level ground.

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Chapter1: Units, Trigonometry. And Vectors
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a. using the launch velocity determined in question 1 or 2 (should be the same!) determine the maximum range of the rocket, with a launch angle of 45 degrees.  *Assume level ground.

b. Compare the value in question 4 with the value for maximum range in the table. Discuss reasons for differences. (even if they happen to be exactly the same!)

 

QUESTION ONE DATA IN PICTURE.

Using conservation of energy,
К. Е., +Р. Е.; — К. Е.f +P. E.f
mv + mgh, = mv + mgh,
where, v; = launch speed
maximum height
h; = initial height = 0 m
hf
%3|
velocity at maximum height = 0m ·s-
Vf =
(
At maximum height velocity of projectile is 0.
substituting values,
zmv + mg (0 m) = ;m (0 ms-') + mgh;
So, above reduces to,
v = gh;
So,
Iaunching velocity (v;) = V2 gh;
substituting numerical values,
Iaunching velocity (v;) = \/2 (9. 8 m · s-2 ) (1. 47 m) = 5. 37 m · s-1
Transcribed Image Text:Using conservation of energy, К. Е., +Р. Е.; — К. Е.f +P. E.f mv + mgh, = mv + mgh, where, v; = launch speed maximum height h; = initial height = 0 m hf %3| velocity at maximum height = 0m ·s- Vf = ( At maximum height velocity of projectile is 0. substituting values, zmv + mg (0 m) = ;m (0 ms-') + mgh; So, above reduces to, v = gh; So, Iaunching velocity (v;) = V2 gh; substituting numerical values, Iaunching velocity (v;) = \/2 (9. 8 m · s-2 ) (1. 47 m) = 5. 37 m · s-1
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