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Using the following equations, solve for the value of "a" eq.1) F - Fr = m*a eq. 2) Fr = 210*R*v eq. 3) R = R0*e^(-t/250) Equiation 1 is an example of Newton's second law where "F" is a constant force, "a" is the acceleration of an object and "Fr" is the friction force of an unknown fluid described in equiation 2, where "v" is an unknown constant.

Using the following equations, solve for the value of "a" eq.1) F - Fr = m*a eq. 2) Fr = 210*R*v eq. 3) R = R0*e^(-t/250) Equiation 1 is an example of Newton's second law where "F" is a constant force, "a" is the acceleration of an object and "Fr" is the friction force of an unknown fluid described in equiation 2, where "v" is an unknown constant.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Using the following equations, solve for the value of "a"

  • eq.1) F - Fr = m*a
  • eq. 2) Fr = 210*R*v
  • eq. 3) R = R0*e^(-t/250)

Equiation 1 is an example of Newton's second law where "F" is a constant force, "a" is the acceleration of an object and "Fr" is the friction force of an unknown fluid described in equiation 2, where "v" is an unknown constant.

"m" is the mass of a sphere of density ρ=8960 [Kg/m3] . The initial radius of said sphere is "R0" and it is reduced according to the equation 3

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