Using the figure below, calculate the minimum mass of potassium nitrate required to form a saturated solution in 250 g of water at 20 °C? 100 e o sa to 20 10 0 0 10 30 KNO, - 40 KCI 50 Temperature *C 60 KCIO, 70 80 90 100

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**Question:**

Using the figure below, calculate the minimum mass of potassium nitrate required to form a saturated solution in 250 g of water at 20 °C.

**Graph Description:**

The graph shows solubility curves for three salts: KNO₃ (potassium nitrate), KCl (potassium chloride), and KClO₃ (potassium chlorate). The x-axis represents temperature in degrees Celsius, ranging from 0 to 100 °C. The y-axis represents solubility in grams of solute per 100 grams of H₂O, ranging from 0 to 100 g/100g H₂O.

- **KNO₃:** The curve for potassium nitrate rises steeply with increasing temperature. At 20 °C, the solubility is approximately 32 g/100g H₂O.
- **KCl:** The curve for potassium chloride is less steep, indicating moderate solubility change with temperature. At 20 °C, it is approximately 34 g/100g H₂O.
- **KClO₃:** This curve is the least steep, with lower solubility at lower temperatures, and intersects the KNO₃ curve around 80 °C.

**Calculation Instruction:**

To find the minimum mass of KNO₃ needed:

1. Determine the solubility of KNO₃ at 20 °C from the graph, which is 32 g/100g H₂O.
2. Since the solution needs to be prepared in 250 g of water, calculate the required mass of KNO₃ using proportional scaling:
   \[
   \text{Mass of KNO₃} = \left( \frac{32 \text{ g KNO₃}}{100 \text{ g H₂O}} \right) \times 250 \text{ g H₂O} = 80 \text{ g KNO₃}
   \]

Thus, 80 grams of potassium nitrate are required to form a saturated solution in 250 grams of water at 20 °C.
Transcribed Image Text:**Question:** Using the figure below, calculate the minimum mass of potassium nitrate required to form a saturated solution in 250 g of water at 20 °C. **Graph Description:** The graph shows solubility curves for three salts: KNO₃ (potassium nitrate), KCl (potassium chloride), and KClO₃ (potassium chlorate). The x-axis represents temperature in degrees Celsius, ranging from 0 to 100 °C. The y-axis represents solubility in grams of solute per 100 grams of H₂O, ranging from 0 to 100 g/100g H₂O. - **KNO₃:** The curve for potassium nitrate rises steeply with increasing temperature. At 20 °C, the solubility is approximately 32 g/100g H₂O. - **KCl:** The curve for potassium chloride is less steep, indicating moderate solubility change with temperature. At 20 °C, it is approximately 34 g/100g H₂O. - **KClO₃:** This curve is the least steep, with lower solubility at lower temperatures, and intersects the KNO₃ curve around 80 °C. **Calculation Instruction:** To find the minimum mass of KNO₃ needed: 1. Determine the solubility of KNO₃ at 20 °C from the graph, which is 32 g/100g H₂O. 2. Since the solution needs to be prepared in 250 g of water, calculate the required mass of KNO₃ using proportional scaling: \[ \text{Mass of KNO₃} = \left( \frac{32 \text{ g KNO₃}}{100 \text{ g H₂O}} \right) \times 250 \text{ g H₂O} = 80 \text{ g KNO₃} \] Thus, 80 grams of potassium nitrate are required to form a saturated solution in 250 grams of water at 20 °C.
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