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Using the equilibrium data for the n-pentane–n-heptane system given in Example 26.3-2, calculate the relative volatility for each concentration and plot α versus the liquid composition xA.

Using the equilibrium data for the n-pentane–n-heptane system given in Example 26.3-2, calculate the relative volatility for each concentration and plot α versus the liquid composition xA.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Using the equilibrium data for the n-pentane–n-heptane system given in Example 26.3-2, calculate the relative volatility for each concentration and plot α versus the liquid composition xA.
EXAMPLE 26.3-2. Simple Differential Distillation A mixture of 100 mol containing 50 mol % n-pentane and 50 mol % n-heptane is distilled under differential conditions at 101.3 kPa until 40 mol are distilled. What is the average composition of the total vapor distilled and the composition of the liquid left? The equilibrium data are as follows, where x and y are mole fractions of n-pentane: X y 1.000 1.000 0.398 0.836 0.059 0.271 0.867 0.984 0.254 0.701 1211 0.594 0.925 0.145 0.521 Solution: The given values to be used in Eq. (26.3-10) are L= 100 mol, x1 = 0.50, L2 60 mol, and V (moles distilled) = 40 mol. Substituting into Eq. (26.3-10), 100
Transcribed Image Text:EXAMPLE 26.3-2. Simple Differential Distillation A mixture of 100 mol containing 50 mol % n-pentane and 50 mol % n-heptane is distilled under differential conditions at 101.3 kPa until 40 mol are distilled. What is the average composition of the total vapor distilled and the composition of the liquid left? The equilibrium data are as follows, where x and y are mole fractions of n-pentane: X y 1.000 1.000 0.398 0.836 0.059 0.271 0.867 0.984 0.254 0.701 1211 0.594 0.925 0.145 0.521 Solution: The given values to be used in Eq. (26.3-10) are L= 100 mol, x1 = 0.50, L2 60 mol, and V (moles distilled) = 40 mol. Substituting into Eq. (26.3-10), 100
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