Using the dissociation constant, Kd = 3.4x1015 calculate the equilibrium concentrations of OH in a 0.0465-M solution of Zn(OH)4-2 O a. 1.8x10-5 M O b.9.1x10-4 M Oc 3.8x10-4 M O d.6.0x10-7 M

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Chapter1: Chemical Foundations
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Using the dissociation constant, Kd = 3.4x10 15, calculate the equilibrium concentrations of OH in a 0.0465-M solution of Zn(OH)42
O a. 1.8x10-5 M
O b.9.1x10-4 M
O c. 3.8x10-4 M
O d. 6.0x10-7 M
Transcribed Image Text:Using the dissociation constant, Kd = 3.4x10 15, calculate the equilibrium concentrations of OH in a 0.0465-M solution of Zn(OH)42 O a. 1.8x10-5 M O b.9.1x10-4 M O c. 3.8x10-4 M O d. 6.0x10-7 M
Using the dissociation constant, Kd 1x1044, calculate the equilibrium concentrations of CN in a 0.333 M solution of Fe(CN)6-.
О а. 1.8х10-5 м
O b. 3.8x10-4 M
O c. 6.0x10-7
M
O d. 9.1x10-4 M
Transcribed Image Text:Using the dissociation constant, Kd 1x1044, calculate the equilibrium concentrations of CN in a 0.333 M solution of Fe(CN)6-. О а. 1.8х10-5 м O b. 3.8x10-4 M O c. 6.0x10-7 M O d. 9.1x10-4 M
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