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Using the circuit below, complete the table while showing your solutions and circuit simplifications. -6 C1 = 1x10 HE F C3 =3x10¬°F -6 F C5 = 5x10 C6 4x10¯º F = -6 2x10 ° F = C2 : C4 -6 = 6x10° F %3D 9x10-6 F = C9 Cg C, = 7x10 -6 F -6 = 8x10 F Ceq = Charge (C) Voltage (V) Q1 = Q2 = Q3 = Q4 = Q5 = Q6 = Q7 = Q8 = Qg = QT = V, = V2 = | V3 = V4 = V5 = V6 = V7 = V3 = V9= AV = 24 V

Using the circuit below, complete the table while showing your solutions and circuit simplifications. -6 C1 = 1x10 HE F C3 =3x10¬°F -6 F C5 = 5x10 C6 4x10¯º F = -6 2x10 ° F = C2 : C4 -6 = 6x10° F %3D 9x10-6 F = C9 Cg C, = 7x10 -6 F -6 = 8x10 F Ceq = Charge (C) Voltage (V) Q1 = Q2 = Q3 = Q4 = Q5 = Q6 = Q7 = Q8 = Qg = QT = V, = V2 = | V3 = V4 = V5 = V6 = V7 = V3 = V9= AV = 24 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Using the circuit below, complete the table while showing your solutions and circuit simplifications. C1 = 1x10 HE F C3 =3x10¬°F H -6 F C5 = 5x10 C6 4x10¬º F = -6 2x10 ° F = C2 : C4 -6 = 6x10° F %3D 9x10-6 F = C9 Cg C, = 7x10 -6 F -6 = 8x10 F Ceq = Charge (C) Voltage (V) Q1 = Q2 = Q3 = Q4 = Q5 = Q6 = Q7 = Q8 = Qg = QT = V, = V2 = | V3 = V4 = V5 = V6 = V7 = V8 = V9 = AV = 24 V
Transcribed Image Text:Using the circuit below, complete the table while showing your solutions and circuit simplifications. C1 = 1x10 HE F C3 =3x10¬°F H -6 F C5 = 5x10 C6 4x10¬º F = -6 2x10 ° F = C2 : C4 -6 = 6x10° F %3D 9x10-6 F = C9 Cg C, = 7x10 -6 F -6 = 8x10 F Ceq = Charge (C) Voltage (V) Q1 = Q2 = Q3 = Q4 = Q5 = Q6 = Q7 = Q8 = Qg = QT = V, = V2 = | V3 = V4 = V5 = V6 = V7 = V8 = V9 = AV = 24 V
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