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d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0

d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please answer the below question explaining each step 

Solve using nodal analysis (preferably) and please see whether my working for nodal analysis is correct or not

 = 0.0238A from A to B 

d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10
Transcribed Image Text:d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10
considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0
Transcribed Image Text:considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0
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