Using the Chinese Remainder Theorem Solve the following: Here is the theorem first: Chinese Remainder Theorem (CRT): Let r, m1, . . . , mr ∈ Z and for all 1 ≤ i ̸= j ≤ r suppose gcd(mi, mj ) = 1. Then for any r integers a1, . . . , ar, the system of linear congruences x = a1 (mod m1) x = a2 (mod m2) . . . x = ar (mod mr) has a solution x ∈ Z and it is unique modulo m1m2 · · · mr, i.e. if y ∈ Z is any other solution, then y = x (mod m1m2 · · · mr). Find the smallest integer a > 2 such that 2 | a, 3 | a + 1, 4 | a + 2,5 | a + 3, and 6 | a +
Using the Chinese Remainder Theorem Solve the following: Here is the theorem first: Chinese Remainder Theorem (CRT): Let r, m1, . . . , mr ∈ Z and for all 1 ≤ i ̸= j ≤ r suppose gcd(mi, mj ) = 1. Then for any r integers a1, . . . , ar, the system of linear congruences x = a1 (mod m1) x = a2 (mod m2) . . . x = ar (mod mr) has a solution x ∈ Z and it is unique modulo m1m2 · · · mr, i.e. if y ∈ Z is any other solution, then y = x (mod m1m2 · · · mr). Find the smallest integer a > 2 such that 2 | a, 3 | a + 1, 4 | a + 2,5 | a + 3, and 6 | a +
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using the Chinese Remainder Theorem Solve the following:
Here is the theorem first:
Chinese Remainder Theorem (CRT): Let r, m1, . . . , mr ∈ Z and for all 1 ≤ i ̸= j ≤ r
suppose gcd(mi, mj ) = 1. Then for any r integers a1, . . . , ar, the system of linear
congruences
x = a1 (mod m1)
x = a2 (mod m2)
.
.
.
x = ar (mod mr)
has a solution x ∈ Z and it is unique modulo m1m2 · · · mr, i.e. if y ∈ Z is any other
solution, then y = x (mod m1m2 · · · mr).
Find the smallest integer a > 2 such that 2 | a, 3 | a + 1, 4 | a + 2,5 | a + 3, and 6 | a + 4
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