Using the applications of the normal distribution, calculate by adding the corresponding graph for: a) The area under the curve to the left when z= 1.83. b) The probability for the variable z when P (-1.43 < z < .68), that is, between -1.43 and 0.68 c) Consider a mean = 1.20 and a standard deviation of 0.15; Determine the probability when 1.00 < x < 1.10, that is, between 1.0 and 1.10

Using the applications of the normal distribution, calculate by adding the corresponding graph for: a) The area under the curve to the left when z= 1.83. b) The probability for the variable z when P (-1.43 < z < .68), that is, between -1.43 and 0.68 c) Consider a mean = 1.20 and a standard deviation of 0.15; Determine the probability when 1.00 < x < 1.10, that is, between 1.0 and 1.10

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Short Answer 1. Use the normal approximation to find u and o in a binomial distribution with n = 1000 and p = 0.5.
If the variable Z is normally distributed with mean equal to 0 and standard deviation equal to 1. The probability that the variable takes a value less than -0.9 or greater than 0.5 is: Select one: P(Z < -0.9 or Z > 0.5) = 0.5074 P(Z < -0.9 or Z > 0.5) = 0.1915 P(Z < -0.9 or Z > 0.5) = 0.3159 P(Z < -0.9 or Z > 0.5) = 0.4926
Central High School believes their students have unusually high SAT scores on average. The school has 165 students.Based on national data, the average SAT score is 1067 with a population standard deviation of 207. Assume SAT scores are normally distributed. Let X be the random variable representing the mean SAT scores for groups of 165 randomly selected students.a. Fill in the blank, rounding your answers to 2 decimal places if needed. According to the Central Limit Theorem, X is approximately normal with a mean of and a standard error of the mean .b. Find the z-score associated to a sample with a mean of 1109, using the sampling distribution. Round your answer to two decimal places. c. Find the probability that a randomly selected sample of 165 students has a mean SAT score higher than 1109. Round your answer to 4 decimal places. d. Central High School finds that for their students, the average SAT score is 1109. Are they justified in saying their students perform unusually well on…
Current Attempt in Progress Let x have a normal distribution with a mean of 57.7 and a standard deviation of 4.95. The z value for x = 43.38, rounded to two decimal places, is: i
Let X be normally distributed with mean = 3.3 and standard deviation o=1.8. a. Find P(X> 6.5). Note: Round your final answer to 4 decimal places. P(X> 6.5) b. Find P(5.5 ≤ x ≤7.5). Note: Round your final answer to 4 decimal places. P(5.5 ≤ x ≤ 7.5)
6.9 To enter the cumulative normal distribution table Þ(Z), calculate Z and Z at the spec limits. upper lower Þ(2) = 0.9772 and Þ(-2) = 0.0228, the area to the right of the USL plus to the left of the LSL is 0.0456.
Answe part d and e
A normal distribution has a mean of=100 with a SD= 20 . If one score is randomly selected from this distribution. What is the probability that the score will have a value between X=100 and X=130? NOTE: Using the z-score table attached
The time that it takes for the next train to come follows a Uniform distribution with f(x) =1/50 where x goes between 2 and 52 minutes. Round answers to 4 decimal places when possible. A. This is a Uniform or Normal distribution? B. Is it a Discrete or Continuous distribution? C. What is the mean of this distribution?
Determine to 3 decimal places the value of x² for 25 degrees of freedom and an area of 0.990 in the left tail of the chi-square distribution curve. x² = i
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. zz 0.26760.2676 0 A symmetric bell-shaped curve is plotted over a horizontal scale with two labeled coordinates. One coordinate is labeled "0" and is located at the center and peak of the curve. The other coordinate is labeled "z," and is to the left of 0. A vertical line extends from the scale to the curve at z. The area under the curve to the left of z is shaded and labeled “0.2676.”