Using standard enthalpy formation/Hess Law, calculate the enthalpy change for the combustion of 1 mol ethanol: C2H5OH (l) + 3 O2 (g) > 2 CO2 (g) + 3 H2O (l)
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Using standard enthalpy formation/Hess Law, calculate the enthalpy change for the combustion of 1 mol ethanol:
C2H5OH (l) + 3 O2 (g) > 2 CO2 (g) + 3 H2O (l)
Given :Balanced combustion reaction of C2H5OH
To find : Enthalpy change for the combustion of 1 mol ethanol.
Solution : As we know that, in the combustion reaction Carbon dioxide and Water are formed as main products. Since Every substance has standard enthalpy of formation so by the use of Hess law, we can calculate standard enthalpy of combustion through substract sum of standards enthalpy of products to sum of standard enthalpy of reactants.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
