Using Slope Deflection Method, determine all reactions at supports also, determine shear and bending moments with complete labels. Use I = 1/12 bh^3 and E = 2.15x10^7 KPa "Wa(1m)" KN "w" KN/m "Wx1/2" KN/m 3.0 m 1.0 m b= 0.45m 3.0 m 3.0 m b= 0.50m 6.0 m b = 0.55m h = 0.65m h= 0.55m h= 0.60m

Q: now complete solution in each forces the given truss, Compute support reactions Compute all member…

A:

Q: Section 0 1 2 Remark VR (m/s) Depth (m) (degrees) - - - Right bank. 1.75 55 1.8 1.84 57 2.5 2.00 60…

A:

Q: An ESP must treat 800,000 acfm with 99.1% efficiency. Assuming an effective drift velocity of 14…

A: Given: The discharge is 800,000 ft3/min. The efficiency is 99.1%. The effective drift velocity is 14…

Q: Assuming the conduit in the figure is a 36” wrought iron pipe flowing full, and that the outlet is…

A: Given wrought iron, the friction factor will be = 0.008Diameter of the pipe  = 36 '' It is asked to…

Q: By route A (3.0 km long) point M is 111.200 m higher than point N. By route B (4.0 km long) M is…

A: To determine the most probable value of the difference in elevation.   Given, Length of route A (LA)…

Q: Calculate the coordinates of the polygon

A: Data given Find : coordinates of the polygon

Q: 40cm dia. 10cm V, = 5m/s V2 water

A:

Q: Find degree of static indeterminacy

A: Given data : The number of member in truss structure m=21 The number of Joint in truss structure…

Q: Draw the Y and M 6m 15 31² diagram 20 kN/m 6M 3j+c 20 amer= so kn эм

A: Given: A frame  Required: Shear force and bending moment diagram

Q: DEPENDENT/RELATIVE MOTION Block A is moving downward with a velocity of 5 m/s. How fast is Block B…

A: Velocity of block A=5 m/s   Now considering a free body diagram of the system of pulley as shown…

Q: 30 KN/m 6 m

A: Given To Find Maximum deflection of beam

Q: 50kn 1,5m 2-N

A: Given,  There is a beam as shown in the figure.  There is a point load which is Acting at the middle…

Q: 6. Using the following data, determine the difference in elevation between BM-15 and BM-16? Station…

A:

Q: How shear is zero at distance of 5.18m explain mathematically

A: It is asked to prove how shear is zero at distance of 5.18m explain mathematically

Q: 7.6 For the following consolidated drained triaxial tests on a clay, draw a p' versus q' diagram and…

A: Given data:Testp' (kN/m2)q' (kN/m2)128.7535.46238.3337.38373.7949.834101.664.25134.276.7Stress parth…

Q: A pipe of Aluminum alloy is subjected to a tensile force F along its longitudinal axis. The pipe has…

A: According to hook's law young modulus E = stress / strain(recoverable) Here given E = 75 Gpa = 75 x…

Q: 20 kN y 30 -x- 45° 8 kN 4 kN Problem 2/80

A:

Q: Find qu Via Terzaghi's equeatioms: JE ア-132 m C =15 ka/m A=20° %3D D=3 m CirCular Shape

A: Foundation is the last supporting part of the structure known as substructure. Footing/foundation is…

Q: The distance from point A to B was measured with a steel tape weighing 3 kg at a temperature of 34°C…

A: Pull applied for measurement = P = 3Kg Standard pull at which the tape was calibrated = P0 = 10Kg…

Q: 35 KN/m 50 KN 1.0 m|1.0 4.0 m R1 R2

A:

Q: a KN/m b KN 2.4 m A 21 31 |41 31 51 b KN a KN/m 3.6 m F| 21 31 41 31 51 G H em em d m

A:

Q: 6 m B 60 kN A 5 m D 60 kN C 5 m F 160 kN E 5 m G

A:

Q: 2. An engineer's level with stadia constant of 0.3 and stadia interval factor of 100 was set up at…

A: stadia constant =c =0.3 stadia interval factor= 100

Q: A circular duct has a diameter of 0.74m. Find the equivalent width and height of rectangular duct…

A: ASKED: To determine the equivalent size of a rectangular duct for a given circular duct.   Given,…

Q: B) RA =, KN, R = KN/m 60 KN/m 55KN 175 KN A 6.00 m R 1.50 m 4.00 m

A:

Q: A. A horizontal distance of 598.25mis to beestablished along a line that slopes at a vertical angle…

A: To determine slope distance should be laid out? Temperature correction per tape length Temperature…

Q: Water flows in a trapezoidal channel with side slope 1V:3H, bottom width of 16ft and water depth of…

A: Area of the channelA=zy2+by=3(4.5)2+16×4.5A=132.75ft2Perimeter:P=B+2y1+z2P=16+2(4.5)1+32P=44.4605ft

Q: 14. For a wide rectangular channel y>>B. a) True b) False

A: Since , AREA(A) = B.y    & Perimeter( P) = B+2y Where B>>y

Q: Water is flowing through a pipe at a pressure of 130 kPa and a velocity of 50 cm/s. what is the…

A: Total head is the summation of pressure head velocity head and that of head.  Let's calculate…

Q: FIND The draft/ depth of Floatation

A:

Q: hing= 20 kN/m 4.

A:

Q: The water-plane area of the ship is 1,679.4m2 with the following half-ordinates commencing from…

A:

Q: For the given force system shown in figure 1, if force P=150kn & force F=300kn, determine the…

A: Since the given question has sub multi parts therefore as per guidelines only 1-3 parts will be…

Q: What is the Lateral Clearance “M”, given the following: R = 30 S = 45m

A: Radius r = 30 Distance s = 45m

Q: 50 kN в 3 m 25 kN 3m A 2 m 4 m

A:

Q: Determine the maximum height, h, perpendicular to the ground. h 55.30 ft/s² 25° 35° 1

A:

Q: 10 m B 60 KN 40 KN 80 KN 30 m 50m- 50m 30m

A:

Q: PROBLEM 4 A truss is loaded with nodal force at C as shown TOS-003. If the truss members have…

A:

Q: Determine the vertical displacement of end A and displacement of B relative to C in a composite A36…

A:

Q: Determine the force of all members using METHOD OF JOINT. Answer in 3 decimal places only. TRUSS…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.