Using Pumping Lemma (slides 30-35 of the notes 'Regular Languages & Finite Automata-IV') one can show the language L= {a"b" |n € N} is not regular (We need this property in the notes 'Context-free Languages and Pushdown Automata I). This is done by way of contradiction. We assume L is regular. Since L is infinite, Pumping Lemma applies. We then consider the string s = ambm where m is the number of states in the DFA that recognizes L. Since the length of s is bigger than m, by Pumping Lemma, there exists strings x,y and z such that s = xyz, y# A, |xy|< 2m and xykz EL for all k e N. If |xy| < 2m then the first repeated state on the acceptance path cannot be a final state. Is this statement true, why or why not?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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2. Using Pumping Lemma (slides 30-35 of the notes 'Regular Languages & Finite
Automata-IV') one can show the language L= {a"b" | n€N } is not regular (We need
this property in the notes 'Context-free Languages and Pushdown Automata I). This is
done by way of contradiction. We assume L is regular. Since L is infinite, Pumping
Lemma applies. We then consider the string s = ambm where m is the number of
states in the DFA that recognizes L. Since the length of s is bigger than m, by Pumping
Lemma, there exists strings x,y and z such that s = xyz, y + A, |xy| < 2m and
xykz eL for all k e N. If |xy| < 2m then the first repeated state on the acceptance
path cannot be a final state. Is this statement true, why or why not?
Transcribed Image Text:2. Using Pumping Lemma (slides 30-35 of the notes 'Regular Languages & Finite Automata-IV') one can show the language L= {a"b" | n€N } is not regular (We need this property in the notes 'Context-free Languages and Pushdown Automata I). This is done by way of contradiction. We assume L is regular. Since L is infinite, Pumping Lemma applies. We then consider the string s = ambm where m is the number of states in the DFA that recognizes L. Since the length of s is bigger than m, by Pumping Lemma, there exists strings x,y and z such that s = xyz, y + A, |xy| < 2m and xykz eL for all k e N. If |xy| < 2m then the first repeated state on the acceptance path cannot be a final state. Is this statement true, why or why not?
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