Using pK, values given in Table 4.1, predict the position of equilibrium in this acid-base reaction and calculate its K H,PO, + CH,CH,OH=H,PO, + CH, CH, OH,+ Table 4.1 pk, Values for Some Organic and Inorganic Acids Acld Formula PK. Conjugate Base CH,CH, Weaker Ethane CH,CH, 51 Stronger conjugate base acid Ethylene CH,=CH, 44 CH=CH Ammonia NH, 38 NH, Hydrogen H, 35 H Acetylene HC=CH 25 HC=C CH,CH,OH CH,CH,0 Ethanol 15.9 Water H,0 15.7 но CH,NH, Methylammonlum lon 10.64 CH,NH, Bicarbonate lon HCO, 10.33 co,?- CH,0 Phenol CH,OH 9.95 Ammontum fon NH, 9.24 NH, Hydrogen sulfide H,S 7.04 HS Pyridinlum C,H,NH 5.2 C,H,N Benzoie acid CH,COOH 4.19 CH,COO Hydrogen fluoride HF 3.2 F- Stronger acid Weaker Phosphorie acid H,PO, 2,1 H,PO, conjugate base p-Toluenesulfonic acid CH,C,H,SO,H CH,C,H,SO, 0.7 Nitric acid HNO, -1.5 NO, Hydronium ion H,0* -1.74 H,0 Sulfuric acid H,SO, -5.2 HSO, Hydrogen chloride HCI -7 CI Hydrogen bromlde HBr -8 Br Hydrogen lodide HI -9.9
Using pK, values given in Table 4.1, predict the position of equilibrium in this acid-base reaction and calculate its K H,PO, + CH,CH,OH=H,PO, + CH, CH, OH,+ Table 4.1 pk, Values for Some Organic and Inorganic Acids Acld Formula PK. Conjugate Base CH,CH, Weaker Ethane CH,CH, 51 Stronger conjugate base acid Ethylene CH,=CH, 44 CH=CH Ammonia NH, 38 NH, Hydrogen H, 35 H Acetylene HC=CH 25 HC=C CH,CH,OH CH,CH,0 Ethanol 15.9 Water H,0 15.7 но CH,NH, Methylammonlum lon 10.64 CH,NH, Bicarbonate lon HCO, 10.33 co,?- CH,0 Phenol CH,OH 9.95 Ammontum fon NH, 9.24 NH, Hydrogen sulfide H,S 7.04 HS Pyridinlum C,H,NH 5.2 C,H,N Benzoie acid CH,COOH 4.19 CH,COO Hydrogen fluoride HF 3.2 F- Stronger acid Weaker Phosphorie acid H,PO, 2,1 H,PO, conjugate base p-Toluenesulfonic acid CH,C,H,SO,H CH,C,H,SO, 0.7 Nitric acid HNO, -1.5 NO, Hydronium ion H,0* -1.74 H,0 Sulfuric acid H,SO, -5.2 HSO, Hydrogen chloride HCI -7 CI Hydrogen bromlde HBr -8 Br Hydrogen lodide HI -9.9
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Using pK, values given in Table 4.1, predict the position of equilibrium in this acid-base
reaction and calculate its K
H,PO, + CH,CH,OH=H,PO, + CH, CH, OH,+

Transcribed Image Text:Table 4.1 pk, Values for Some Organic and Inorganic Acids
Acld
Formula
PK.
Conjugate Base
CH,CH,
Weaker
Ethane
CH,CH,
51
Stronger
conjugate base
acid
Ethylene
CH,=CH,
44
CH=CH
Ammonia
NH,
38
NH,
Hydrogen
H,
35
H
Acetylene
HC=CH
25
HC=C
CH,CH,OH
CH,CH,0
Ethanol
15.9
Water
H,0
15.7
но
CH,NH,
Methylammonlum lon
10.64
CH,NH,
Bicarbonate lon
HCO,
10.33
co,?-
CH,0
Phenol
CH,OH
9.95
Ammontum fon
NH,
9.24
NH,
Hydrogen sulfide
H,S
7.04
HS
Pyridinlum
C,H,NH
5.2
C,H,N
Benzoie acid
CH,COOH
4.19
CH,COO
Hydrogen fluoride
HF
3.2
F-
Stronger
acid
Weaker
Phosphorie acid
H,PO,
2,1
H,PO,
conjugate base
p-Toluenesulfonic acid
CH,C,H,SO,H
CH,C,H,SO,
0.7
Nitric acid
HNO,
-1.5
NO,
Hydronium ion
H,0*
-1.74
H,0
Sulfuric acid
H,SO,
-5.2
HSO,
Hydrogen chloride
HCI
-7
CI
Hydrogen bromlde
HBr
-8
Br
Hydrogen lodide
HI
-9.9
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