Using only 3 ARM instructions without using any LDR or STR instructions, show how to store the current value of the frame pointer in the stack, make the frame pointer to point to the base of this frame, and create an 8-byte stack frame while the stack pointer to point to the top of the stack. Assume that an FD stack is in use, appropriate stack space is already allocated to the stack, and the stack pointer is appropriately initialized. The first instruction is The second instruction is The third instruction is O Mark for Review What's This?

Using only 3 ARM instructions without using any LDR or STR instructions, show how to store the current value of the frame pointer in the stack, make the frame pointer to point to the base of this frame, and create an 8-byte stack frame while the stack pointer to point to the top of the stack. Assume that an FD stack is in use, appropriate stack space is already allocated to the stack, and the stack pointer is appropriately initialized. The first instruction is The second instruction is The third instruction is O Mark for Review What's This?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Translate the following C code into RISC-V assembly code. You can only use RV64I and RV64M instructions and cannot use pseudoinstuctions. Note that according to RISC-V spec, “In the standard RISC-V calling convention, the stack grows downward and the stack pointer is always kept 16-byte aligned.”.long long int func(int n) { if (n == 0 or n == 1 or n == 2)return n; else return n*n + func(n - 1) + 8*func(n - 2) + func(n - 3);}
Please provide a brief explanation of the stack pointer register and the role it plays.
In a few words, describe the stack pointer register and its function.
The STACK is a dynamic data structure. The 80x86 computer controls its stack via stack pointer ESP. Whenever you PUSH data onto the stack segment memory using PUSH EBX, the 80x86 will transfer data by: Decreasing the stack pointer ESP by 4. O b. Incrcasing the stack pointer ESP by 2. Decreasing the stack pointer ESP by 2. Increasing the stack pointer ESP by 4.
For the base and offset addresses in previous problem, how many words of data are currently held in the stack ? (Previous Problem): If the current value of the stack segment register and stack pointer are C00016 and FF 0016, respec- tively, what is the address of the current top of the stack ?
The STACK is a dynamic data structure. The 80x86 computer controls its stack via stack pointer ESP. Whenever you POP data out of the stack segment memory using POP BX, the 80x86 will transfer data by: Increasing the stack pointer ESP by 4. a. b. Decreasing the stack pointer ESP by 4. Decreasing the stack pointer ESP by 2. C. d. Increasing the stack pointer ESP by 2.
In simple words, describe the stack pointer register.
Let us assume that, the stack pointer ($sp) has value Y, just before the procedure starts. Give the value, of the stack pointer, with respect to Y, after the procedure saves the appropriate registers on stack. Give the value and explain why. Give the value, of the stack pointer, with respect to Y, after the procedure restores the saved registers from stack. Give the value and explain why.
Register Name Register Contents Memory Address Memory Contents EAX 13 12A2h EBX 11 38 ECX 21 184 B004h EDX 95 8004h seeah ESP
main() uses t0, t1, t2, s0, B() uses t4, s3, s4, C() uses t1, t2, t3, t4, s0, s5. How many words on the stack are needed when main() calls B() and B() calls C()? (ignore frame pointer register ($fp))
For the (pseudo) assembly code below, replace X, Y, P, and Q with thesmallest set of instructions to save/restore values on the stack and update the stackpointer. Assume that procA and procB were written independently by two differentprogrammers who are following the MIPS guidelines for caller-saved and callee-savedregisters. In other words, the two programmers agree on the input arguments andreturn value of procB, but they can't see the code written by the other person. procA:$s0 = ...$s1 = ...$s2 = ...$t0 = ...$t1 = ...$t2 = ...X$a0 = ...$a1 = ...jal procBY... = $s1... = $t0... = $t1... = $a0jr $raprocB:P... = $a0... = $a1$s2 = ...$t0 = ...Qjr $ra
61. If the current values in the stack segment register and stack pointer are C00016 and FF0016, respectively, what is the address of the current top of the stack?