Using node analysis, determine the model equation for Vout in terms of Vpot. Using the model equation, calculate the Vout for each value of Vpot. www R9 V3 10K Vpot 9Vde R8 U2 1k Vout SET = 0.5 OUT %3D OPAMP R7 Rô 10k 1k

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### Node Analysis and Op-Amp Circuit Explanation

#### Objective:
To determine the model equation for \( V_{\text{out}} \) in terms of \( V_{\text{pot}} \) using node analysis, and calculate \( V_{\text{out}} \) for each value of \( V_{\text{pot}} \).

#### Circuit Description:
The circuit comprises a power source, resistors, a potentiometer, and an operational amplifier (op-amp). 

- **Power Source:** 9V DC supply.
- **Resistors:** 
  - \( R9 = 10k\Omega \)
  - \( R8 = 1k\Omega \)
  - \( R7 = 10k\Omega \)
  - \( R6 = 1k\Omega \)

- **Potentiometer:** \( \text{SET} = 0.5 \), which determines the wiper position for \( V_{\text{pot}} \).

- **Op-Amp Configuration:**
  - Non-inverting terminal (+) connected to \( V_{\text{pot}} \) through \( R8 \).
  - Feedback is provided from the output \( V_{\text{out}} \) through \( R6 \) to the inverting terminal (-).
  - Additional feedback through \( R7 \).

#### Procedure:

1. **Node Analysis:**
   - Apply Kirchhoff's laws to find relationships between voltages and currents in the circuit.
   - Use the properties of the op-amp, assuming ideal conditions \( V_{\text{+}} = V_{\text{-}} \).

2. **Equation Derivation:**
   - Use the voltage divider rule for \( V_{\text{pot}} \) and apply gain equations for the op-amp to find \( V_{\text{out}} \) in terms of \( V_{\text{pot}} \).

3. **Calculation:**
   - Substitute different values of \( V_{\text{pot}} \) to obtain corresponding \( V_{\text{out}} \).

### Key Concepts:
- **Op-Amp Properties:** In an ideal op-amp, the input impedance is infinite, and the output is driven to balance the input differential voltage, resulting in \( V_{\text{+}} = V_{\text{-}} \).
- **Voltage Divider Rule:** Used to calculate \( V_{\text{pot}} \) from the potentiometer configuration.

This exercise
Transcribed Image Text:### Node Analysis and Op-Amp Circuit Explanation #### Objective: To determine the model equation for \( V_{\text{out}} \) in terms of \( V_{\text{pot}} \) using node analysis, and calculate \( V_{\text{out}} \) for each value of \( V_{\text{pot}} \). #### Circuit Description: The circuit comprises a power source, resistors, a potentiometer, and an operational amplifier (op-amp). - **Power Source:** 9V DC supply. - **Resistors:** - \( R9 = 10k\Omega \) - \( R8 = 1k\Omega \) - \( R7 = 10k\Omega \) - \( R6 = 1k\Omega \) - **Potentiometer:** \( \text{SET} = 0.5 \), which determines the wiper position for \( V_{\text{pot}} \). - **Op-Amp Configuration:** - Non-inverting terminal (+) connected to \( V_{\text{pot}} \) through \( R8 \). - Feedback is provided from the output \( V_{\text{out}} \) through \( R6 \) to the inverting terminal (-). - Additional feedback through \( R7 \). #### Procedure: 1. **Node Analysis:** - Apply Kirchhoff's laws to find relationships between voltages and currents in the circuit. - Use the properties of the op-amp, assuming ideal conditions \( V_{\text{+}} = V_{\text{-}} \). 2. **Equation Derivation:** - Use the voltage divider rule for \( V_{\text{pot}} \) and apply gain equations for the op-amp to find \( V_{\text{out}} \) in terms of \( V_{\text{pot}} \). 3. **Calculation:** - Substitute different values of \( V_{\text{pot}} \) to obtain corresponding \( V_{\text{out}} \). ### Key Concepts: - **Op-Amp Properties:** In an ideal op-amp, the input impedance is infinite, and the output is driven to balance the input differential voltage, resulting in \( V_{\text{+}} = V_{\text{-}} \). - **Voltage Divider Rule:** Used to calculate \( V_{\text{pot}} \) from the potentiometer configuration. This exercise
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