12.67KN/mFigure 02C3.26mb2= 0.30m2.40mh2= 0.35m19m, KNb1= 0.40m9.67mh1= 0.40mb3=0.45m6.75mh3=0.45m15.2KN/m AD Using Moment Distribution Method for all figures, determine MAB, MBA, MBc, McB, McD, Mpc and allreactions at support. Use I = 1/12 b(h³) and E = 2.10x107 KPaUsing Slope Deflection Method for all figures, determine MAB, MBA, MBc, McB, McD, MDc and allreactions at support. Use I = 1/12 b(h³) and E = 2.10x10' KPa

Answered: Image /qna-images/answer/3f7653ba-4d59-4671-92e8-7117ab702e3f.jpg

Using Moment Distribution Method for all figures, determine MAB, MBA, MBC, MCB, McD, MDC and all reactions at support. Use I=1/12 b(h³) and E = 2.10x10² KPa Using Slope Deflection Method for all figures, determine MAB, MBA, MBC, MCB, MCD, MDc and all reactions at support. Use I=1/12 b(h³) and E = 2.10x10' KPa

Using Moment Distribution Method for all figures, determine MAB, MBA, MBC, MCB, McD, MDC and all reactions at support. Use I=1/12 b(h³) and E = 2.10x10² KPa Using Slope Deflection Method for all figures, determine MAB, MBA, MBC, MCB, MCD, MDc and all reactions at support. Use I=1/12 b(h³) and E = 2.10x10' KPa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

For the forces acting on the beam shown in Figure 3.1f, determine the location of the equivalent resultant force with reference to point A in m. Given / = 2.4, P1 = 8, P2 = 8 and w = 2 %3D (Note: Prefix the answer with negative sign "." if the location is to the left of the reference point. E.g. if the location of the equivalent resultant is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) P, kN W kN/m P, kN C 21 m 21 m Figure 3.1f
Use x = 137 y = 37 a = 6 b = 8 c = 1
With a=4 b=1 c=1
The uniform beam has a mass of 41 kg per meter of length. Determine the reactions at the supports. A Your answer is partially correct. Ay= Bx= By= y Answers: 1282.856 i 2454.754 2.5 m N N N 1.2 m 340 kg B
Determine the moments over the supports using three moment equation. Also determine the support reactions. The answers are given show the solution *USE THREE MOMENT EQUATION
Solve for the reactions, the midspan deflection, and the slope at the midspan. Use E = 70 GPa and I = 100 x 106 mm4 Final Equations with value of C1 and C2 EIy'' = EIy' = EIy = RA: RB: MA: Deflection: Slope:
Use X = 137 Y = 37 A = 6 B = 8 C = 1
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=1.50 m, b=5.00 m, PA = 75kN, and PC = 90kN. Construct the shear-force and bending-moment diagrams. Calculate the reaction forces By and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below.
A beam supported by three identical springs at points A,B,C (see figure). Given that flexural of rigidity of the beam, EI= 2.029X1011 N.mm2 ; spring constant,k = 1471.5N/mm, w=116N/mm All dimensions are in mm. 1. What is the reaction for at point A,B and C? 2. What is the deflection at point B? 3. Please draw shear-force and bending moment diagram.
Show solution with detailed Free body diagram/drawings.
For the forces acting on the beam shown in Figure 3.1h, determine the location of the equivalent resultant force with reference to point A in m. Givenl= 2.4, P1 = 45, P2 = 90, w1= 40 and w2 = 60. (Note: Prefix the value with negative sign "-" if the location is to the left of the reference point. E.g. if the location of the equivalent resultant is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) P, kN P2 kN W, kN/m W, kN/m C Im 21 m 21 m Figure 3.1h
SOLVE THE FOLLOWING PROBLEM AND SHOW YOUR COMPLETE SOLUTIONS. EXPLAIN YOUR ANSWER FOR BETTER UNDERSTANDING.