16 5. Determine the resultant force on the body, P in the concurrent force shown in Figure 2.48 using calculation and graphical methods. 300N 450N 30% 700N 30° 450 60º 750N 200N Figure 2.48 Solution: 223 N. 6. Determine the reactions at the supports of the beam shown in Figure 2.49. Solutions: Ray = 574.7N, Roy = 394.9N and Rpx = 300N(+) 600N 60° 50N/m T Figure 2.49 2m 100N 3m 2m 7. Determine the resultant and equilibrant of the concurrent system of forces shown in Figure 2.50, using analytical and graphical methods. Solutions: R4KN; 0 =17°44'; E = -4KN 4KN 60° 145° 2KN 20% 3KN 5KN Figure 2.50 8. Determine the tensions in the two ropes C and D as shown in Figure 2.51? Figure 2.51 45° 600 16 Solutions: T = 25.6N,T₂ = 36.2N D 50N 9. The inclined beam AC shown in Figure 2.52 is pinned at B and held in equilibrium by the load at C, Compute the moment of the vertical force at C about the fulcrum at B? B A 20 KN 2.5m C Figure 2.52 Solution: M=43.3KNm 10. Shown in Figure 2.53 is a system of cord and pulley carrying two blocks in equilibrium. Assuming pulley C is frictionless, compute the tension in cord AB and the mass M? Figure 2.53 B I M E .50 Kg Solutions: TAB=981N, M = 141.2N 11. Determine the reactions at the supports of the beam shown in Figure 2.54. Solutions: Ray = 3.5KN, Ray = 6.5KN.Rax = 5.2KN(+-) 6KN 4KN B 3KN/m
16 5. Determine the resultant force on the body, P in the concurrent force shown in Figure 2.48 using calculation and graphical methods. 300N 450N 30% 700N 30° 450 60º 750N 200N Figure 2.48 Solution: 223 N. 6. Determine the reactions at the supports of the beam shown in Figure 2.49. Solutions: Ray = 574.7N, Roy = 394.9N and Rpx = 300N(+) 600N 60° 50N/m T Figure 2.49 2m 100N 3m 2m 7. Determine the resultant and equilibrant of the concurrent system of forces shown in Figure 2.50, using analytical and graphical methods. Solutions: R4KN; 0 =17°44'; E = -4KN 4KN 60° 145° 2KN 20% 3KN 5KN Figure 2.50 8. Determine the tensions in the two ropes C and D as shown in Figure 2.51? Figure 2.51 45° 600 16 Solutions: T = 25.6N,T₂ = 36.2N D 50N 9. The inclined beam AC shown in Figure 2.52 is pinned at B and held in equilibrium by the load at C, Compute the moment of the vertical force at C about the fulcrum at B? B A 20 KN 2.5m C Figure 2.52 Solution: M=43.3KNm 10. Shown in Figure 2.53 is a system of cord and pulley carrying two blocks in equilibrium. Assuming pulley C is frictionless, compute the tension in cord AB and the mass M? Figure 2.53 B I M E .50 Kg Solutions: TAB=981N, M = 141.2N 11. Determine the reactions at the supports of the beam shown in Figure 2.54. Solutions: Ray = 3.5KN, Ray = 6.5KN.Rax = 5.2KN(+-) 6KN 4KN B 3KN/m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
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Please solve no 6 and 10 step by step solution
Transcribed Image Text:16
5. Determine the resultant force on the body, P in the concurrent force shown in Figure 2.48 using
calculation and graphical methods.
300N
450N
30%
700N
30°
450
60º
750N
200N
Figure 2.48
Solution: 223 N.
6. Determine the reactions at the supports of the beam shown in Figure 2.49.
Solutions: Ray = 574.7N, Roy = 394.9N and Rpx = 300N(+)
600N
60°
50N/m
T
Figure 2.49
2m
100N
3m
2m
7. Determine the resultant and equilibrant of the concurrent system of forces shown in Figure 2.50, using
analytical and graphical methods.
Solutions: R4KN; 0 =17°44'; E = -4KN
4KN
60°
145°
2KN
20%
3KN
5KN
Figure 2.50
8. Determine the tensions in the two ropes C and D as shown in Figure 2.51?
Figure 2.51
45°
600
16
Solutions: T = 25.6N,T₂ = 36.2N
D
50N
9. The inclined beam AC shown in Figure 2.52 is pinned at B and held in equilibrium by the load at C,
Compute the moment of the vertical force at C about the fulcrum at B?
B
A
20 KN
2.5m
C
Figure 2.52
Solution: M=43.3KNm
10. Shown in Figure 2.53 is a system of cord and pulley carrying two blocks in equilibrium. Assuming
pulley C is frictionless, compute the tension in cord AB and the mass M?
Figure 2.53
B
I
M
E
.50 Kg
Solutions: TAB=981N, M = 141.2N
11. Determine the reactions at the supports of the beam shown in Figure 2.54.
Solutions: Ray = 3.5KN, Ray = 6.5KN.Rax = 5.2KN(+-)
6KN
4KN
B
3KN/m
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