Using loop analysis knd. Vou ZmA ov Zv IKR Vo the

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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**Problem Statement:**

Using loop analysis, find \( V_0 \).

**Circuit Description:**

The circuit consists of the following components:

1. **Resistors:**
   - A 1 kΩ resistor on the leftmost vertical branch.
   - A 2 kΩ resistor in series with a 1 kΩ resistor on the vertical branch between loops 1 and 2.
   - A 1 kΩ resistor on the rightmost vertical branch.

2. **Current Sources:**
   - A 4 mA current source pointing upwards in the leftmost vertical branch.
   - A 2 mA current source pointing downwards in the rightmost vertical branch.

3. **Voltage Sources:**
   - A 12 V voltage source in the horizontal branch between loops 1 and 2.
   - A 6 V voltage source in the horizontal branch between loops 2 and 3.

**Loops:**

- **Loop 1**: Consists of the 4 mA current source, a 2 kΩ resistor, and a 12 V voltage source.
- **Loop 2**: Shared with a 2 kΩ resistor and a 1 kΩ resistor.
- **Loop 3**: Consists of a 1 kΩ resistor, a 2 mA current source, and a 6 V voltage source.

**Objective:**

Determine the output voltage \( V_0 \) across the rightmost 1 kΩ resistor using loop analysis technique.
Transcribed Image Text:**Problem Statement:** Using loop analysis, find \( V_0 \). **Circuit Description:** The circuit consists of the following components: 1. **Resistors:** - A 1 kΩ resistor on the leftmost vertical branch. - A 2 kΩ resistor in series with a 1 kΩ resistor on the vertical branch between loops 1 and 2. - A 1 kΩ resistor on the rightmost vertical branch. 2. **Current Sources:** - A 4 mA current source pointing upwards in the leftmost vertical branch. - A 2 mA current source pointing downwards in the rightmost vertical branch. 3. **Voltage Sources:** - A 12 V voltage source in the horizontal branch between loops 1 and 2. - A 6 V voltage source in the horizontal branch between loops 2 and 3. **Loops:** - **Loop 1**: Consists of the 4 mA current source, a 2 kΩ resistor, and a 12 V voltage source. - **Loop 2**: Shared with a 2 kΩ resistor and a 1 kΩ resistor. - **Loop 3**: Consists of a 1 kΩ resistor, a 2 mA current source, and a 6 V voltage source. **Objective:** Determine the output voltage \( V_0 \) across the rightmost 1 kΩ resistor using loop analysis technique.
Expert Solution
Step 1 To find Vo

Draw the circuit:

Electrical Engineering homework question answer, step 1, image 1

To find Vo apply KVL in the loop 1:

Vo+6-12=0Vo=6V

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