Open-circuit120.0V0.290A8.778WShort-circuit6.848V2.017A13.36WData at secondaryOpen-circuit48.01V0.624A7.694WShort-circuit2.827V5.032A13.14WData at primary1.) Calculate the tums ratio from the transfomer primary/secondary voltage ratingsa=2.) Using the open-circuit data at the primary and the short-circuit data at the secondary, calculatethe four transformer parameters (to 3 significant figures)RelXelRclXml3.) Using the open-circuit data at the secondary and the short-circuit data at the primary, calculatethe four transformer parameters (to 3 significarnt figures)RelXelRelXml

For better utilization of transformer core and for good efficiency, Important parameters of…

Open-circuit 120.0V 0.290A 8.778W Short-circuit 6.848V 2.017A 13.36W Data at secondary Open-circuit Short-circuit 48.01V 0.624A 7.694W 2.827V 5.032A 13.14W Data at primary 1.) Calculate the tums ratio from the transformer primary/secondary voltage ratings a=

Open-circuit 120.0V 0.290A 8.778W Short-circuit 6.848V 2.017A 13.36W Data at secondary Open-circuit Short-circuit 48.01V 0.624A 7.694W 2.827V 5.032A 13.14W Data at primary 1.) Calculate the tums ratio from the transformer primary/secondary voltage ratings a=

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

90KVA, 460/230 3Phase transformer, Determine the Primary Conductor Size (include the AWG size number), Secondary Conductor Size (include the AWG size number), Primary Protection Breaker, and Secondary Protection Breaker. uarn
3. Single-phase T1-transformer with a power of 500 kVA and a single-phase T2- with a power of 400 kVAtransformers are connected in parallel and load 1000 kVA with 0.8-back power factor.they are feeding. The equivalent circuit winding resistance of T1 is 0.025 b and the equivalent circuit reactance is 0.06is b. The equivalent winding resistance of T2 is 0.016 b and the equivalent circuit reactance is 0.07 b. Bothhas the same conversion ratio in the transformer.a. Draw the connection diagram given in the question. b. Obtain the power sharing expression over the parameters given in the question. c. Calculate the kVA values and power factors of the transformers.
Three phase, single phase visible on the side of high voltage (primary) windings of 50 Hz 34500/10500 /Y connected transformerequivalent circuit parameters are given below. Each of the low voltage (secondary) windings of this transformerWhen a star-connected resistive load of 7.5 ohms is connected and a nominal voltage is applied to high-voltage windingsfind the transformer efficiency. Total iron losses for three phases will be 85000 WInternal resistance of primary winding (?1) 1,85ohmPrimary winding leakage reactant (?1) 1,25ohmSecondary winding internal resistance (moved to Primary) (?2') 1,82ohmSecondary winding leakage reactant (primere moved) (?2') 1,25ohm
Q 3-phase step down transformer 1200 KVA , 11000/2200 V, 50 Hz . The resistance /phase and leakage reactance/phase of the primary winding are 0.82 and 4.8N and the corresponding values for the secondary winding are 0.012 and 0.06N respectively if the primary winding is connected in delta and secondary in star calculate: i)The voltage to be applied at normal frequency to the primary to circulate full-load through it when the secondary is short-circuited ii) The full load copper loss
Given this transformer with load, what is the expected phase of the primary and secondary voltage? Why?
The algebraic symbol for the number of turns on the high voltage side of the transformer is_____. A) Th, B) TX, C)T-Primary, D) T-Secondary. The algebraic symbol for the current through the low voltage winding is ____. A) IH, B) IX, C) I-Primary, D) I-Secondary Whic of the following is information that is found on an AC generator's nameplate? A) voltage, current, B) frequency, number of phase, speed rating, C) maximum temperature rise, excitation requirements, D) all of the above
What happened to 3-phase delta configuration of transformer when any one of the phases is opened due to the fault. Also, explain a brief operation along with the appropriate phasor diagram. Draw the phasor diagram along with the connection for Dd6 and Ydi
Q5/C: Compare between Auto transformers and 2 winding transformers.
A single phase 9.6 kVA, 500 V / 1.5 kV transformer has an impedance of 1.302 Ω with respect to primary side. and secondary sides. Find its per-unit impedance with respect to primary side only a. 0.02 b. 0.03 c. 0.04 d. 0.05
A low voltage distribution transformer feeds two different loads with a three-phase line. The nominal voltage of the line is 400 Volt. The total length of the feeder is 500 m. The distance from the transformer to these loads is 140 m and 340 m, respectively. Their consumption is 11 kVA with a 0.8 lagging power factor and 10 kW with a 0.8 lagging power factor, respectively. The feeder's cross-section is 15 mm2 and the feeder's conductivity is 56 m/ohm.mm2. Find the following information. The distance from the transformer to the maximum voltage drop point is m The maximum voltage drop is Volt The power loss between the transformer and 11 kVA load is Watt.
In small transformers, the total copper loss may vary from the rated output. % of O 0.2 to 0.6 O 0.5 to 1 O 0.8 to 1.5 O 0.4 to 1
A short transmission line connects a step-up transformer on the source side with a series impedance of j0.5 ohms (referred to the primary) to a step-down transformer on the load side with a series impedance of 50 ohms (referred to the primary). The turn ratio of the step-up transformer is 1:10 and a no-load primary voltage of 13.2 (line-to-line) kv. The step-down transformer has a turn ratio of 15:1 and it has a Y-connected, balanced load of 0.667 +j 0.111 ohms connected to its secondary side. A capacitor bank of -j0.239 ohms is added parallel to the load. Assuming an ideal transmission line, the effective impedance of the system (per phase) seen by the source would be: O A. 0.093 + j0.249 O B. 0.372 + j0.996 OC.3.72 + j9.96 O D. None of the other choices are correct O E. 0.186 + j0.498