Using KVL, determine the unknown branch voltages in the circuit below. 20 V + V3 www + mu + 5 1 V1 5 V + +1 V2 M + 8 V
Using KVL, determine the unknown branch voltages in the circuit below. 20 V + V3 www + mu + 5 1 V1 5 V + +1 V2 M + 8 V
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
Sign Convention
Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.
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![### Educational Text on Kirchhoff's Voltage Law (KVL) Application
#### Problem Statement:
Using KVL, determine the unknown branch voltages in the circuit below.
#### Circuit Description:
The circuit consists of a loop with the following components:
1. A 20 V voltage source.
2. A resistor with voltage \( V3 \).
3. A resistor with voltage \( V2 \).
4. A resistor with voltage \( V1 \).
5. An 8 V voltage source.
6. A 5 V voltage source.
#### Explanation:
- The circuit is a closed loop containing both voltage sources and resistors.
- The positive and negative polarities of each component are marked, indicating the assumed direction of voltage drops across the resistors.
#### KVL Application:
Kirchhoff’s Voltage Law states that the sum of the electromotive forces and potential differences (voltages) around any closed network is zero. For this circuit, the KVL equation is:
\[ 20V - V3 - V1 + 5V - V2 - 8V = 0 \]
This equation can be rearranged to solve for the unknown voltages \( V1 \), \( V2 \), and \( V3 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc77db10-411b-4277-b72e-b2214a4cc0f7%2F7a109af6-663e-4e05-847c-1573fb523587%2Fstv7jcr_processed.png&w=3840&q=75)
Transcribed Image Text:### Educational Text on Kirchhoff's Voltage Law (KVL) Application
#### Problem Statement:
Using KVL, determine the unknown branch voltages in the circuit below.
#### Circuit Description:
The circuit consists of a loop with the following components:
1. A 20 V voltage source.
2. A resistor with voltage \( V3 \).
3. A resistor with voltage \( V2 \).
4. A resistor with voltage \( V1 \).
5. An 8 V voltage source.
6. A 5 V voltage source.
#### Explanation:
- The circuit is a closed loop containing both voltage sources and resistors.
- The positive and negative polarities of each component are marked, indicating the assumed direction of voltage drops across the resistors.
#### KVL Application:
Kirchhoff’s Voltage Law states that the sum of the electromotive forces and potential differences (voltages) around any closed network is zero. For this circuit, the KVL equation is:
\[ 20V - V3 - V1 + 5V - V2 - 8V = 0 \]
This equation can be rearranged to solve for the unknown voltages \( V1 \), \( V2 \), and \( V3 \).
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