Using Java, can you provide an algorithm of the 0-1 Knapsack using the Backtracking method.
Using Java, can you provide an algorithm of the 0-1 Knapsack using the Backtracking method.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Using Java, can you provide an

Transcribed Image Text:Suppose that n =
4, W16, and we have the following:
i
1
2
3
4
Pi
W₂
$20
$6
$50 10 $5
$10 5
W₂
Pi
$40
2
$30 5
![void knapsack (index i,
{
if
}
}
int profit, int
(weight <= W && profit >
marprofit profit;
numbest i;
=
bestset
include;
if (promising (i)) {
include [i+1]
knapsack(i+1,
include [ + 1]
knapsack(i+1, profit, weight);
}
bool promising (index i)
{
index j, k;
int totweight;
float bound;
if (weight >= W)
return false;
else {
weight)
marprofit){
"yes";
profit + p[i+1], weight + w[i+1]);
"no":
j=i+1;
bound profit;
totweight
weight;
while (j<= n && totweight + w[j] <= W){
totweight = totweight + w[i];
bound bound + p[j];
j++;
}
k = ji
if (k <=n)
bound = bound (W- totweight)
return bound > maxprofit;
// This set is best
// so far.
// Set numbest to
// number of items
// considered. Set
// bestset to this
// solution.
*
// Include w[i+1].
// Do not include
// w[i+1].
// Node is promising only
// if we should expand to
// its children. There must
// be some capacity left for
// the children.
// Grab as many items as
// possible.
// Use k for consistency
// with formula in text.
p[k]/w[k];
// Grab fraction of kth
// item.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9c5c685-36ee-4fac-af4d-fd04868f8e6a%2F739d233e-ef72-4c02-8059-baa9477f1913%2Frw87m7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:void knapsack (index i,
{
if
}
}
int profit, int
(weight <= W && profit >
marprofit profit;
numbest i;
=
bestset
include;
if (promising (i)) {
include [i+1]
knapsack(i+1,
include [ + 1]
knapsack(i+1, profit, weight);
}
bool promising (index i)
{
index j, k;
int totweight;
float bound;
if (weight >= W)
return false;
else {
weight)
marprofit){
"yes";
profit + p[i+1], weight + w[i+1]);
"no":
j=i+1;
bound profit;
totweight
weight;
while (j<= n && totweight + w[j] <= W){
totweight = totweight + w[i];
bound bound + p[j];
j++;
}
k = ji
if (k <=n)
bound = bound (W- totweight)
return bound > maxprofit;
// This set is best
// so far.
// Set numbest to
// number of items
// considered. Set
// bestset to this
// solution.
*
// Include w[i+1].
// Do not include
// w[i+1].
// Node is promising only
// if we should expand to
// its children. There must
// be some capacity left for
// the children.
// Grab as many items as
// possible.
// Use k for consistency
// with formula in text.
p[k]/w[k];
// Grab fraction of kth
// item.
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