Using integration by parts, [4x²2x dx

Q: 2 х3 +3х6 1 x4

A: Explanation of the solution is given below...

Q: (х3 + 3х)dx х1/2

A: Thus the integration is a process of finding anti derivative of a function . There are basically two…

Q: Evaluate 3 | ((2 – 1)32, (3 + t)2, 1)dx. 3/2 3/2 -3

A:

Q: dx 3/2 3

A:

Q: x4 「高。 dx x2+1 Find

A:

Q: x5 + 1 dx x4 + 2x3

A:

Q: VALUATE xx4 dX 3

A: to find:- integration of the given function. *concept:- let,  x^3+4 = t.

Q: 10 dx 7. S 4x3-4x2+5x

A: We use partial fraction method

Q: 2X + 2 ) dx 3. 2X 6 + 2e

A:

Q: dx (x. + 1) Vx + 3

A: Evaluate I=∫dxx+1x+3

Q: (² X x2 + 4x + 13 dx

A:

Q: x²+2x - 1 dx 2x3 + 3x2 - 2x

A:

Q: 5 x´ - 9 -9- +2)x dx X 5.

A:

Q: •B Find 2xVx- 5 dx, where B > 3.

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Q: 4 12+5X- 14 dx

A:

Q: 5. J 3 V.

A: Our Aim is to evaluate the integral given below:-∫dxx73-(i)

Q: 1 x2 - x + 12 x3 + 3x dx

A:

Q: S (7z³ + 4x²) dx

A:

Q: Sts dx 4+x4 4 4 V2

A: ∫54254  x4+x4dxlet   x2=t differntiate on both sides…

Q: 1 X x2 – a 2 dx

A:

Q: - Trig Sub x5 dx (36x2 + 1)ž

A:

Q: Integrate x sqrt of (x+4) dx using algebraic substitution

A:

Q: Evaluate.

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Q: 3- f xvx2 +1 dx

A: Integration

Q: (1 +Iпx) dx x3

A: The given integral is ∫1+ln xx3dx. Here, u=1+ln x  and  v=1x3.

Q: fx x tan x dx

A: We can find the integration using integration by parts as below.

Q: dx 28. 1– x4

A:

Q: 3log; x (16x² – 6)1²dx =

A: It is known that ∫xndx=xn+1n+1+C, where C is the integration constant.