Using induction, show that the cardinality of the powerset of A is 2" where n is the number of elements in A. In other words, given a set A with |A| = n then |P(A)| helpful to see the practice problem on induction to see what is required of your proof). = 2". (You may find it

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
icon
Concept explainers
Topic Video
Question

need help with this questions. I have attached the practice problem as guidance

Using induction, show that the cardinality of the powerset of A is 2" where n is the number of
elements in A. In other words, given a set A with |A| = n then |P(A)| = 2". (You may find it
helpful to see the practice problem on induction to see what is required of your proof).
Transcribed Image Text:Using induction, show that the cardinality of the powerset of A is 2" where n is the number of elements in A. In other words, given a set A with |A| = n then |P(A)| = 2". (You may find it helpful to see the practice problem on induction to see what is required of your proof).
Using induction, show that n! < n" for all n > 1. (You may find it helpful to see the practice
problem on induction to see what is required of your proof).
Solution:
We use induction on a sequence of statements:
• 2! < 22 (statement 2)
• 3! < 33 (statement 3)
• n! < n" (statement n)
Base Case (statement 2):
2! = 2 * 1 = 2 < 4 = 2²
so that 2! < 22
Inductive Step: Assume statement n is true, that is n! < n". Then:
(n +1)! = n! * (n + 1)
< п" * (п+1)
< (n +1)" * (п + 1)
= (n +1)"+1
Where we use statement n in the second line and the fact that n" < (n +1)" in the third (since n
is positive). This statement shows that (n +1)! < (n + 1)"n+1.
By induction, n! < n" for all n > 1.
Transcribed Image Text:Using induction, show that n! < n" for all n > 1. (You may find it helpful to see the practice problem on induction to see what is required of your proof). Solution: We use induction on a sequence of statements: • 2! < 22 (statement 2) • 3! < 33 (statement 3) • n! < n" (statement n) Base Case (statement 2): 2! = 2 * 1 = 2 < 4 = 2² so that 2! < 22 Inductive Step: Assume statement n is true, that is n! < n". Then: (n +1)! = n! * (n + 1) < п" * (п+1) < (n +1)" * (п + 1) = (n +1)"+1 Where we use statement n in the second line and the fact that n" < (n +1)" in the third (since n is positive). This statement shows that (n +1)! < (n + 1)"n+1. By induction, n! < n" for all n > 1.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Sample space, Events, and Basic Rules of Probability
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,