Solve for the DMD, 2A DMD, and area of the given table using the DMD method. USING COMPASS RULEINCLUDEDLENGTHCORRECTION CORRECTIONCORRECTEDCORRECTEDANGLELINEFORE BEARING BACK BEARINGLATITUDEDEPARTUREANGLE(m)IN LATIN DEPLATITUTDEDEPARTURES 57° ES 35°S'12" WN 77°47'36" WA102* 50' 18"AB13.2N 57° W7.189-11.07-0.574-2.2986.615-13.368B87° 54' 48"BC17.42N 35°5'12" E14.25410.013-0.758-3.03213.4966.981S 77°47'36" ES 52°46'54" ES 45°50'18" W112° 52' 48"CD10-2.1149.774-0.435-1.741-2.5498.033D154° 59' 18"DE13.9N 52°46'54" W-8.40711.069-0.605-2.419-9.0128.650-10.2960.00081° 22' 48"EA11.55N 45°50'18" E-8.047-8.286-0.503-2.010-8.550Σ66.072.87511.50.000

USING COMPASS RULE INCLUDED LENGTH CORRECTION CORRECTION CORRECTED CORRECTED NGLE LINE FORE BEARING BACK BEARING LATITUDE DEPARTURE ANGLE (m) IN LAT IN DEP LATITUTDE DEPARTURE 102* 50' 18" 87° 54' 48" S 57° E S 35°S'12" W A АВ 13.2 N 57° W 7.189 -11.07 -0.574 -2.298 6.615 -13.368 B BC 17.42 N 35°5'12" E 14.254 10.013 -0.758 -3.032 13.496 6.981 S 77°47'36" E S 52°46'54" E S 45°50'18" W 112° 52' 48" CD 10 N 77°47'36" W -2.114 9.774 -0.435 -1.741 -2.549 8.033 D 154° 59' 18" DE 13.9 N 52°46'54" W -8.407 11.069 -0.605 -2.419 -9.012 8.650 E 81° 22' 48" EA 11.55 N 45°50'18" E -8.047 -8.286 -0.503 -2.010 -8.550 -10.296 66.07 2.875 11.5 0.000 0.000

USING COMPASS RULE INCLUDED LENGTH CORRECTION CORRECTION CORRECTED CORRECTED NGLE LINE FORE BEARING BACK BEARING LATITUDE DEPARTURE ANGLE (m) IN LAT IN DEP LATITUTDE DEPARTURE 102* 50' 18" 87° 54' 48" S 57° E S 35°S'12" W A АВ 13.2 N 57° W 7.189 -11.07 -0.574 -2.298 6.615 -13.368 B BC 17.42 N 35°5'12" E 14.254 10.013 -0.758 -3.032 13.496 6.981 S 77°47'36" E S 52°46'54" E S 45°50'18" W 112° 52' 48" CD 10 N 77°47'36" W -2.114 9.774 -0.435 -1.741 -2.549 8.033 D 154° 59' 18" DE 13.9 N 52°46'54" W -8.407 11.069 -0.605 -2.419 -9.012 8.650 E 81° 22' 48" EA 11.55 N 45°50'18" E -8.047 -8.286 -0.503 -2.010 -8.550 -10.296 66.07 2.875 11.5 0.000 0.000

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please help me solve my STRUCTURAL THEORY problem. Please follow the instructions strictly and please write legibly. Use only SLOPE DEFLECTION METHOD
Structural analysis
I need the answer as soon as possible
Situation #1: Find the value of the diameter at point B. d, = 150 mm V = 1.5 m/s A B d, = ? V, = 2.5 m/s
Determine the y-coordinate of the centroid of the shaded area.
Steel bars and an aluminum bar support the rigid slab as a platform as shown below. A gap A= 0.26 mm %3D exists between the aluminum bar and the slab. Neglecting the weight of the slab a (/degree celsius) 11.6x10* 23.1x10* A (mm²) E (GPa) Steel bar Aluminum bar 350 200 400 70 a) Which temperature increase AT is required to just close the spacing at the middle? (Note that the temperature increase will subject all bars) b) What are the stresses in the steel bars and aluminum bar for AT = 90 degree celsius in MPa? 1000 mm Steel Aluminum Steel
Using Double Integration Method derive an expression for the following: a) Reaction at propped support b) Wall moment c) Mid-span deflection
3) With the same symbols as problem (2), is the equation v = /2gr dimensionally consistent? 4) A rectangular parallelepiped has sides of lengths 2.00 m, 3.00 m, and 4.00 m. Another has sides 2.02 m, and 4.04 m. Find the difference in their volumes. To how many significant figures is the 3.03 m, difference known?
for the beam shwon in figure , compute 1- the slope of the beam at B 2- the deflection of the beam at Use the integration method
Explain the following terms briefly:(i) Displacement thickness.(ii) Von Karman Approximation Method in determining the boundary layer parameters(iii) Lift and Drag Forces.