Use your calculator to find critical values such that the following statements are true. Your task is to a. P(-/2 stst/2) = 0.95, where df = 17 b. P(ts-t) =0.01, where df = 6 c.P (ts-/2 or 12/2) = 0.10, where df = 7 d. P (ts-a/2 or 12t/2) = 0.01, where df = 6 Click the icon to view the table of critical values of t. (Use 3 decimal places in all questions please.) (Use 3 decimal places in questions a-d please.) a. The upper tail critical value a/2 = - b. The lower tail critical value = c. The upper tail critical value ta/2 The lower tail critical value a/2 d. The upper tail critical value a/2 = The lower tailcritical value ₁/2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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Hi, this is a stats problem kindly help me ill rate you all parts please and if possible in text so i can copy or else please skip

Use your calculator to find critical values such that the following statements are true. Your task is to determine the critical values below.
a. P(-a/2 ststa/2) = 0.95, where df = 17
b. P (ts-t)=0.01, where df = 6
c. P(ts-/2 or t2t/2) = 0.10, where df=7
d. P (ts-/2 or 12/2) = 0.01, where df = 6
Click the icon to view the table of critical values of t.
(Use 3 decimal places in all questions please.)
(Use 3 decimal places in questions a-d please.).
a. The upper tail critical value a/2 = -
b. The lower tail critical value =
c. The upper tail critical value a/2= 0
The lower tail critical value a/2 =
d. The upper tail critical value a/2=
The lower tail critical value t₁/2 =
BOXER
Transcribed Image Text:Use your calculator to find critical values such that the following statements are true. Your task is to determine the critical values below. a. P(-a/2 ststa/2) = 0.95, where df = 17 b. P (ts-t)=0.01, where df = 6 c. P(ts-/2 or t2t/2) = 0.10, where df=7 d. P (ts-/2 or 12/2) = 0.01, where df = 6 Click the icon to view the table of critical values of t. (Use 3 decimal places in all questions please.) (Use 3 decimal places in questions a-d please.). a. The upper tail critical value a/2 = - b. The lower tail critical value = c. The upper tail critical value a/2= 0 The lower tail critical value a/2 = d. The upper tail critical value a/2= The lower tail critical value t₁/2 = BOXER
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