Use your calculator to find critical values such that the following statements are true. Your task is to a. P(-/2 stst/2) = 0.95, where df = 17 b. P(ts-t) =0.01, where df = 6 c.P (ts-/2 or 12/2) = 0.10, where df = 7 d. P (ts-a/2 or 12t/2) = 0.01, where df = 6 Click the icon to view the table of critical values of t. (Use 3 decimal places in all questions please.) (Use 3 decimal places in questions a-d please.) a. The upper tail critical value a/2 = - b. The lower tail critical value = c. The upper tail critical value ta/2 The lower tail critical value a/2 d. The upper tail critical value a/2 = The lower tailcritical value ₁/2
Use your calculator to find critical values such that the following statements are true. Your task is to a. P(-/2 stst/2) = 0.95, where df = 17 b. P(ts-t) =0.01, where df = 6 c.P (ts-/2 or 12/2) = 0.10, where df = 7 d. P (ts-a/2 or 12t/2) = 0.01, where df = 6 Click the icon to view the table of critical values of t. (Use 3 decimal places in all questions please.) (Use 3 decimal places in questions a-d please.) a. The upper tail critical value a/2 = - b. The lower tail critical value = c. The upper tail critical value ta/2 The lower tail critical value a/2 d. The upper tail critical value a/2 = The lower tailcritical value ₁/2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hi, this is a stats problem kindly help me ill rate you all parts please and if possible in text so i can copy or else please skip
Transcribed Image Text:Use your calculator to find critical values such that the following statements are true. Your task is to determine the critical values below.
a. P(-a/2 ststa/2) = 0.95, where df = 17
b. P (ts-t)=0.01, where df = 6
c. P(ts-/2 or t2t/2) = 0.10, where df=7
d. P (ts-/2 or 12/2) = 0.01, where df = 6
Click the icon to view the table of critical values of t.
(Use 3 decimal places in all questions please.)
(Use 3 decimal places in questions a-d please.).
a. The upper tail critical value a/2 = -
b. The lower tail critical value =
c. The upper tail critical value a/2= 0
The lower tail critical value a/2 =
d. The upper tail critical value a/2=
The lower tail critical value t₁/2 =
BOXER
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