Use Thévenin's theorem to determine the current through the 300-0 resistor in the circuit of Figure 10-26. 2200 1500 1100 300 500, 300 V unit:- Ohm
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- The battery voltage is 66.9 V, and the resistances are R1 = 163 Ohms; R2 = 83 Ohms; R3 = 167 Ohms; R4 = 174 Ohms; R5 = 86 Ohms; and R6 = 60 Ohms. What is the equivalent resistance of this circuit? 198 Ohms 585 Ohms 315 Ohms 449 OhmsShown in the figure below is an electrical circuit containing three resistors and two batteries. 1₁ I₁ = 4 0 = 13 ww R3 R₂ www 1₂ Write down the Kirchhoff Junction equation and solve it for I₁ in terms of I2 and I3. Write the result here: 12-13 X R₁ ww R3 = 132 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. 4+1₂R₂-13R3 + The resistors in the circuit have the following values: • R₁ = 32 • R₂=452 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4V, R₂, and R₁. 0 = 4-1₁R₁-12R₂ Solve for all the following (some answers may be negative): I1 Amperes I2 = Amperes I3 = AmperesFor the following circuit: Calculate : a) The equivalent resistance of the circuit. b) Total circuit current. c) The currents I2 and I3. d) Voltages V1, V2 and V3.
- In the circuit shown below E = 70.0 V, R5 = 4.00 0, R3 = 2.00 0, R2 = 2.20 0, I5 = 8.80 A, I4 = 5.40 A, and I1 = 12.1 A. Find the current through R2 and R3, and the values of the resistors R1 and Ra- A A Ra R- R3 R- ww I4 ww Rg ww - -1 wwI need detail solutionQuestion 1 What is the equivalent resistance of the circuit shown in the figure? The battery is ideal and all resistances are accurate to 3 significant figures. R₁ V R5 O 950 Ohms O767 Ohms R6 100 257 Ohms O 450 Ohms = 300 Ω www 100 Ω ww = R₂ R3 200 Ω www www www 100 Ω 4 pt www R4 = 150 Ω s 4
- The circuit consists of a battery (V0 = 6.00 V) and five resistors (R1 = 611 Ohms, R2 = 482 Ohms, R3 = 163 Ohms, R4 = 734 Ohms, and R5 = 365 Ohms). What is the current for point D, point B, and point F?Given the equation, V = Voe RC. , what size of resistor would be required to dirop the voltage on a 120mFapacitor to its original valtage in 5 min? Select one Oa R= 1.5 k2 Ob. R= 1.8 kS2 O. R= 1.7 k S O d. R= 1.6 k S2P 4.2-4 Consider the circuit shown in Figure P 4.2-4. Find values of the resistances R₁ and R₂ that cause the voltages v₁ and v₂ to be v₁ = 1 V and v₂ = 2 V. 3 mA Figure P 4.2-4 500 Ω m R2 5 mA
- See the above circuit diagram to answer the question. The battery voltage is V = 90.7 V; R1 = 184 Ohms; R2 = 72 Ohms; R3 = 166 Ohms; R4 = 50 Ohms; R5 = 104 Ohms; and R6 = 98 Ohms. How much power flows through resistor R6? 3.231 W 0.831 W 2.308 W 1.385 WThe circuit shown below has a 15 V battery connected to two resistors in series with R1 - 100 Ω and R, -10 Ω. R1 Ry What is the total equivalent resistance Rtot of the circuit? Rtot = Ω Submit Answer Tries 0/2 What are the magnitudes of the currents I1 and I2 in resistors R1 and R2, respectively? I1 = I2 = %3D Submit Answer Tries 0/2 What are the magnitudes of the potentials V, and V, across resistors R1 and R2, respectively? V1 = V2 = AA > >In the circuit shown below, R1=10 N, R2=32 Q. Ω. Find the equivalent resistance of this circuit: Reg = A. Find the current passing through the R1 resistor: I1= A. Find the current passing through the 5-2 resistor: 15= W. Find the power dissipated on the 5-0 resistor: P5= 10 Q 50 60 V + 10 Q R2 R1 R2