Use the worked example above to help you solve this problem. Consider three point charges at the corners of a triangle, as shown in the figure, where q₁ = 6.31 x 10⁹ C, 92 = -1.78 x 10-⁹ C, and 93 = 4.53 x 10-8 C. (a) Find the components of the force F23 exerted by 92 on 93. F23x = -4.53e-8 F23y 0 (b) Find the components of the force F13 exerted by 91 on 93. F13x = 8.21e-8 N F13y 6.19e-8 N N N (c) Find the resultant force on 93, in terms of components and also in terms of magnitude and direction. Fx = 3.68e-8 N F, = 6.19e-8 N magnitude 7.2e-8 N direction 59.3 EXERCISE HINTS: GETTING STARTED | I'M STUCK! Using the same triangle, find the vector components of the electric force on 9₁ and the vector's magnitude and direction. (Use the charges given in the Practice It section.) N N N • counterclockwise from the +x-axis Fy magnitude direction 0

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 Using the same triangle, find the vector components of the electric force on q1 and the vector's magnitude and direction. (Use the charges given in the Practice It section.) (USE IMAGES PROVIDED FOR PREWORK AND GRAPH)

Find, in terms of N

  • F
  • Fy
  • magnitude 
  • direction (direction must be counterclockwise from the + x-axis 
92
3.00 m
91
I
4.00 m
5.00 m
F₂
29
F18
37°
F18 Cos 37°
98
X
F18 sin 37°
Transcribed Image Text:92 3.00 m 91 I 4.00 m 5.00 m F₂ 29 F18 37° F18 Cos 37° 98 X F18 sin 37°
Use the worked example above to help you solve this problem. Consider three point charges at the
corners of a triangle, as shown in the figure, where q₁ = 6.31 x 10⁹ C, 92= -1.78 x 109 C, and
93 = 4.53 x 10-8 C.
(a) Find the components of the force F23 exerted by 92 on 93.
F23x = -4.53e-8
F23y = 0
(b) Find the components of the force F13 exerted by 91 on 93.
F13x = 8.21e-8 N
N
F13y
(c) Find the resultant force on 93, in terms of components and also in terms of magnitude and
direction.
Fx =
3.68e-8
6.19e-8
magnitude 7.2e-8
direction 59.3
Fy
EXERCISE
= 6.19e-8
=
Fy
magnitude
direction
N
N
=
N
N
N
Using the same triangle, find the vector components of the electric force on 9₁ and the vector's magnitude
and direction. (Use the charges given in the Practice It section.)
Fx =
N
N
N
• counterclockwise from the +x-axis
HINTS: GETTING STARTED I'M STUCK!
Transcribed Image Text:Use the worked example above to help you solve this problem. Consider three point charges at the corners of a triangle, as shown in the figure, where q₁ = 6.31 x 10⁹ C, 92= -1.78 x 109 C, and 93 = 4.53 x 10-8 C. (a) Find the components of the force F23 exerted by 92 on 93. F23x = -4.53e-8 F23y = 0 (b) Find the components of the force F13 exerted by 91 on 93. F13x = 8.21e-8 N N F13y (c) Find the resultant force on 93, in terms of components and also in terms of magnitude and direction. Fx = 3.68e-8 6.19e-8 magnitude 7.2e-8 direction 59.3 Fy EXERCISE = 6.19e-8 = Fy magnitude direction N N = N N N Using the same triangle, find the vector components of the electric force on 9₁ and the vector's magnitude and direction. (Use the charges given in the Practice It section.) Fx = N N N • counterclockwise from the +x-axis HINTS: GETTING STARTED I'M STUCK!
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