Use the van der Waals equation to calculate the pressure, in atm, of 37.49 mol of hydrogen at 108 °C in a 1.65L container. Values of van der Waals Constants for Some Common Gases atm L2 a mol? bl mol Gas Не 0.034 0.0237 H2 N2 O2 Cl2 CO2 CH4 0.244 0.0266 0.0391 0.0318 1.39 1.36 6.49 0.0562 3.59 0.0427 2.25 0.0428 Answer:

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### Van der Waals Equation Application

**Problem Statement:**
Use the van der Waals equation to calculate the pressure, in atm, of 37.49 mol of hydrogen at 108 °C in a 1.65 L container.

**Van der Waals Constants for Some Common Gases:**

| Gas  | \( a \, \left(\frac{\text{atm} \cdot \text{L}^2}{\text{mol}^2}\right) \) | \( b \, \left(\frac{\text{L}}{\text{mol}}\right) \) |
|------|------------------------------------------------|----------------------------------------------|
| He   | 0.034                                          | 0.0237                                       |
| H₂   | 0.244                                          | 0.0266                                       |
| N₂   | 1.39                                           | 0.0391                                       |
| O₂   | 1.36                                           | 0.0318                                       |
| Cl₂  | 6.49                                           | 0.0562                                       |
| CO₂  | 3.59                                           | 0.0427                                       |
| CH₄  | 2.25                                           | 0.0428                                       |

**Calculation:**

1. Convert temperature from Celsius to Kelvin:
   \[
   T(K) = 108 + 273.15 = 381.15 \, K
   \]

2. Use the van der Waals equation to find the pressure \( P \):
   \[
   \left( P + \frac{an^2}{V^2} \right) \times (V - nb) = nRT
   \]
   where,
   - \( n = 37.49 \, \text{mol} \)
   - \( V = 1.65 \, \text{L} \)
   - \( R = 0.0821 \, \frac{\text{L atm}}{\text{mol K}} \)
   - \( a = 0.244 \, \frac{\text{atm} \cdot \text{L}^2}{\text{mol}^2} \)
   - \( b = 0.0266 \, \frac{\text{L}}{\text{mol}} \)
   - \( T = 381.15 \, K \
Transcribed Image Text:### Van der Waals Equation Application **Problem Statement:** Use the van der Waals equation to calculate the pressure, in atm, of 37.49 mol of hydrogen at 108 °C in a 1.65 L container. **Van der Waals Constants for Some Common Gases:** | Gas | \( a \, \left(\frac{\text{atm} \cdot \text{L}^2}{\text{mol}^2}\right) \) | \( b \, \left(\frac{\text{L}}{\text{mol}}\right) \) | |------|------------------------------------------------|----------------------------------------------| | He | 0.034 | 0.0237 | | H₂ | 0.244 | 0.0266 | | N₂ | 1.39 | 0.0391 | | O₂ | 1.36 | 0.0318 | | Cl₂ | 6.49 | 0.0562 | | CO₂ | 3.59 | 0.0427 | | CH₄ | 2.25 | 0.0428 | **Calculation:** 1. Convert temperature from Celsius to Kelvin: \[ T(K) = 108 + 273.15 = 381.15 \, K \] 2. Use the van der Waals equation to find the pressure \( P \): \[ \left( P + \frac{an^2}{V^2} \right) \times (V - nb) = nRT \] where, - \( n = 37.49 \, \text{mol} \) - \( V = 1.65 \, \text{L} \) - \( R = 0.0821 \, \frac{\text{L atm}}{\text{mol K}} \) - \( a = 0.244 \, \frac{\text{atm} \cdot \text{L}^2}{\text{mol}^2} \) - \( b = 0.0266 \, \frac{\text{L}}{\text{mol}} \) - \( T = 381.15 \, K \
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