Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached 0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the pressure of the F2 remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula of the xenon fluoride? (MTS 2/2/2018) O XEF3 O XeF2 O XEF4 O Xe2F O Xe3F O Xe4F

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a
pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its
pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached
0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the
pressure of the F, remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula
of the xenon fluoride?
(MTS 2/2/2018)
O XEF3
XeF2
O XeF4
O Xe2F
O Xe,F
O Xe4F
Transcribed Image Text:Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached 0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the pressure of the F, remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula of the xenon fluoride? (MTS 2/2/2018) O XEF3 XeF2 O XeF4 O Xe2F O Xe,F O Xe4F
Expert Solution
Step 1

Dalton's law of partial pressure states that the total pressure equals to the sum of the partial pressure of the individual gases that makes up the mixture. 

Thus, Total pressure= Pressure of Xenon + Pressure of Fluoride 

P= PXe + PF2

Substituting known, 

0.72 = 0.12 + PF2

Thus, PF2 = 0.60 atm

 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Mole Concept
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY