Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached 0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the pressure of the F2 remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula of the xenon fluoride? (MTS 2/2/2018) O XEF3 O XeF2 O XEF4 O Xe2F O Xe3F O Xe4F
Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached 0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the pressure of the F2 remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula of the xenon fluoride? (MTS 2/2/2018) O XEF3 O XeF2 O XEF4 O Xe2F O Xe3F O Xe4F
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a
pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its
pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached
0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the
pressure of the F, remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula
of the xenon fluoride?
(MTS 2/2/2018)
O XEF3
XeF2
O XeF4
O Xe2F
O Xe,F
O Xe4F](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5db6601-e204-409e-923e-f4567f3ac2a8%2F994888f5-f94f-4b02-99a2-c8e10fd4775e%2Fm36ckn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a
pressure-proof container. Assume that xenon gas was added to a 0.25 liter container until its
pressure reached 0.12 atm at 0.0°C. Fluorine gas was then added until the total pressure reached
0.72 atm at 0.0°C. After the reaction was complete, the xenon was consumed completely, and the
pressure of the F, remaining in the container was 0.48 atm at 0.0°C. What is the empirical formula
of the xenon fluoride?
(MTS 2/2/2018)
O XEF3
XeF2
O XeF4
O Xe2F
O Xe,F
O Xe4F
Expert Solution
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Step 1
Dalton's law of partial pressure states that the total pressure equals to the sum of the partial pressure of the individual gases that makes up the mixture.
Thus, Total pressure= Pressure of Xenon + Pressure of Fluoride
PT = PXe + PF2
Substituting known,
0.72 = 0.12 + PF2
Thus, PF2 = 0.60 atm
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