Use the values in the table to calculate the area between g and h using left-end points for 0 ≤ x ≤ 5. X 0 1 2 3 4 5 6 f(x) g(x) h(x) 5 6 6 4 3 2 2 2122345 589 Sa 6 6 5 4 2
Use the values in the table to calculate the area between g and h using left-end points for 0 ≤ x ≤ 5. X 0 1 2 3 4 5 6 f(x) g(x) h(x) 5 6 6 4 3 2 2 2122345 589 Sa 6 6 5 4 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:### Calculating the Area Between Functions g(x) and h(x) Using Left-End Points
To find the area between the functions \( g(x) \) and \( h(x) \) for the interval \( 0 \leq x \leq 5 \), using left-end points, refer to the table values provided:
#### Table of Values:
| \( x \) | \( f(x) \) | \( g(x) \) | \( h(x) \) |
|--------|-----------|------------|-----------|
| 0 | 5 | 2 | 5 |
| 1 | 6 | 1 | 6 |
| 2 | 6 | 2 | 8 |
| 3 | 4 | 2 | 6 |
| 4 | 3 | 3 | 5 |
| 5 | 2 | 4 | 4 |
| 6 | 2 | 5 | 2 |
### Steps to Calculate Area:
1. **Identify the left endpoints**: Since we are using left-end points, consider the x-values at the beginning of the intervals (0, 1, 2, 3, 4).
2. **Calculate differences**: For each interval, calculate \( h(x) - g(x) \) at the left end:
- At \( x = 0 \): \( h(0) - g(0) = 5 - 2 = 3 \)
- At \( x = 1 \): \( h(1) - g(1) = 6 - 1 = 5 \)
- At \( x = 2 \): \( h(2) - g(2) = 8 - 2 = 6 \)
- At \( x = 3 \): \( h(3) - g(3) = 6 - 2 = 4 \)
- At \( x = 4 \): \( h(4) - g(4) = 5 - 3 = 2 \)
3. **Calculate the area**: Sum up the differences, multiply by the width of each interval (assuming each interval is of width 1):
- Total Area \( = 1 \times (3
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