Approximate the area under graph (a) of f(x)=1/x over the interval [2,10] by computing the area of each rectangle to four decimal places and then ad Approximate the area under graph (b) of f(x) = 1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then ad Q 0.25 The area under graph (a) is approximately (Round to four decimal places as needed.) (a) f(x)=1/x² 0.125+ 0- 6 10-11x2 0.25 125- A 10 (b) X Q Q
Approximate the area under graph (a) of f(x)=1/x over the interval [2,10] by computing the area of each rectangle to four decimal places and then ad Approximate the area under graph (b) of f(x) = 1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then ad Q 0.25 The area under graph (a) is approximately (Round to four decimal places as needed.) (a) f(x)=1/x² 0.125+ 0- 6 10-11x2 0.25 125- A 10 (b) X Q Q
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![a) Approximate the area under graph (a) of f(x) = 1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then adding.
b) Approximate the area under graph (b) of f(x)=1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then adding.
C
Ay
Ⓒ
The area under graph (a) is approximately
(Round to four decimal places as needed.)
(a)
f(x)=1/x²
10
(b)
((x)=1/x²
5
( 8 9 10
0.25
0.125-
0
Ау
0.25
0.125-
o
→ □](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff1c25a98-37d4-4c02-b656-1290cb79c629%2F4e3b1c5b-c368-4fb3-82a1-e8553541850e%2Fse9jbkp_processed.png&w=3840&q=75)
Transcribed Image Text:a) Approximate the area under graph (a) of f(x) = 1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then adding.
b) Approximate the area under graph (b) of f(x)=1/x² over the interval [2,10] by computing the area of each rectangle to four decimal places and then adding.
C
Ay
Ⓒ
The area under graph (a) is approximately
(Round to four decimal places as needed.)
(a)
f(x)=1/x²
10
(b)
((x)=1/x²
5
( 8 9 10
0.25
0.125-
0
Ау
0.25
0.125-
o
→ □
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