Use the unified soil classification system to classify the soil with 65% of the soil sample retained on No 4 Sieve, 30% retained on No 200 Sieve, Cu 3 and Cc=0.9.Also the LL = 28% and PL = 24.5% THE GROUP NAME IS
Q: Q.2) Classify the following soil using the Unified Soil Classification System (USCS): Sieve No. 4 10…
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Q: 4. Classify the following soil by the Unified Soil Classification System: Percent passing No.4 sieve…
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![Use the unified soil classification system to classify the soil with 65% of the soil sample retained on No 4 Sieve, 30%
retained on No 200 Sieve, Cu=3 and Cc-0.9.Also the LL = 28% and PL = 24.5%
THE GROUP NAME IS](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa74bec16-9b20-4469-b1c9-846864ba45ec%2Fe9f527f9-fa8b-4bd6-9173-4b2a2a8d9de6%2Fko0rzzc_processed.png&w=3840&q=75)
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- The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-ML2. Determine the Unified Soil Classification System (USCS) classification for the following inorganic soil. [Ans. CH]. A. Grain Size Distribution Test. Percent Sieve No. 4 10 20 40 60 100 200 Passing (%) 100 100 99 95 93 88 86 B. Plastic Limit Test Tare Number Wt. Wet Soil + Tare (g) Wt. Dry Soil + Tare (g) Wt. of Tare (g) C. Liquid Limit Test Determination Number of Blows Water Content (%) 1 2 6.54 7.24 5.40 5.95 1.17 1 18 69 1.17 2 27 64 3 34 616- For an inorganic soil, the following grain-size analysis is given. U.S. Sieve No. Percent passing 4 100 06 64 10 20 40 38 80 200 18 13 For this soil, LL = 23 and PL = 19. Classify the soil by using a. AASHTO soil classification system b. Unified soil classification system Give group names and group symbols.
- A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO system and the Unified Soil classification system. Liquid Limit = 33% Plastic Limit = 27% %3D %3D Mechanical grain-size analysis: Sieve No. Percentage Passing 4 90 10 77 40 65 200 12Classify the soil by IS classification Given:- Liquid limit=22% Plasticity limit=19% Percentage passing through 4.75mm IS sieve=98.5% Percentage passing through 75 micron IS sieve=35% D60=0.22 D30=0.19 D10=0.16The soil tested at the laboratory was found that the particle passing sieve No.200 is 89%, retained on sieve No. 4 is 3%, Liquid limit of 70%, organic matter of 25%, and Plasticity Index of 40%. Determine the type of soil * PLASTICITY CHART 60 50 CH A LINE: Pl 0,73(LL-20)| 30 CL MH&OH 20 CL ML ML&OL 10 20 30 40 50 60 70 80 90 100 LIQUID LIMIT (LL) (%) O Organic clay O Clay with high plasticity O Organic Silt O Sandy Clay PLASTICITY INDEX (PI) (%)
- For an inorganic soil, the following grain-size analysis is given. Knowing that the liquid limit is 23, and Plastic limit is 19. AASHTO soil classification system. Give the group index. I Unified soil classification system. Give group symbol and group name (specific classification). U.S. sieve no. Percent passing 4 100 10 90 20 64 40 38 80 18 200 13Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.AASHTO SOIL CLASSIFICATION (by AASHTO) AASHTO = American Association of State Highway and Transport Officials Situation 2 Classification of Highway Subgrade Materials % FINER SOIL B SIEVE General classification Granular materials (35% or less of total sample passing No. 200) SOIL A SOIL C 10 83 100 90 A-1 А-2 Procedure: 40 48 92 76 Group classification A-1-a А-1-b А-3 A-2-4 A-2-5 A-2-6 A-2-7 O Group Classification with required test data in mind, proceed from left to right, in chart. The correct group will be found by process of elimination. The first group from the left consistent with the test data is the corect classification. 86 34 Sieve analysis (percentage passing) No. 10 200 20 LL 20 70 37 50 max. 30 max. No. 40 No. 200 Characteristics of fraction PI 32 18 50 max. 51 min. 15 max. 25 max. 10 max. 35 max. 35 max. 35 max. 35 max. Using AASHT0 method: 1. Determine the group symbol and index for soil A. 2. Determine the group symbol and index for soil B. 3. Determine the group symbol…
- Classify the given soils using the Unified Soil Classification System (USCS). Give the group symbols and group names. (Show the path of the classification.) Sieve Analysis (percent finer) Soil No. No. 4 No. 200 LL PL Comments A 94 3 NP Cy = 4.48 and C = 1.22 - В 100 77 63 25 B.Classify this Soil Sample accoring to Unified Soil Classification System Soil Sample 1 Percentage Sieve No.4 60% Sieve No.200 42% Liquid Limit 28% Plasticity Index 4.5% Topic Soil Classification (Soil Mechanics). Show full solutionProblem 6: For an inorganic soil, the following grain-size analysis is given. Knowing that the liquid limit is 23, and Plastic limit is 19. AASHTO soil classification system. Give the group index. Unified soil classification system. Give group symbol and group name (specific classification). U.S. sieve no. Percent passing 4 100 10 90 20 64 40 38 80 18 200 13
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