Use the technology display to make a decision to reject or fail to reject the null hypothesis at a=0.01. Make the decision using the standardized test statistic and using the P-value. Assume the sample sizesare equalClick the icon to view the technology display.Choose the correct answer below.O A. Reject the null hypothesis because the P-value is less than the level of significance.OB. Reject the null hypothesis because the P-value is greater than the level of significanceOC. Fail to reject the null hypothesis because the P-value is greater than the level of significanceOD. Fail to reject the null hypothesis because the P-value is less than the level of significanceCHITechnology Outputμ1> μ2z 2.609496821p=0.0045337744x1 = 47x2 = 44In1=452-SampZTestPrintDone- X Technology Outputµ1 > µ2z=2.609496821P=0.0045337744x1=47x2 = 44↓n1=452-SampZTestPrintDone-X

The level of significance is 0.01.

Answered: Use the technology display to make a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Claim more than 25% of a class is majoring into Nursing (or Nursing-BSN). Test at the 0.5 significance level. Complete the full hypotheses test answering all the questions here. You can use the traditional or p- value method. Sort out the data. 1. What type of test will need to be used? 2. What is the sample size, n, for major? How many business (including business management) majors, X? Use "=counta" instead of "=count" to count qualitative data 3. Hypothesis test . . • Hypotheses • Ho Ha Critical value* ← Test Value (or p-value) Decision *Skip if your using the p-value method. Summary/conclusion 4. Is there a possible type I or type II error? 5. What can you conclude about business majors from this hypothesis test?
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PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. In a study of 796 randomly selected medical malpractice lawsuits, it was found that 489 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? A. H0: p>0.5 H1: p=0.5 B. H0: p<0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p>0.5 E. H0: p=0.5 H1: p<0.5 F. H0: p=0.5 H1: p≠0.5 What is the test statistic? Z=≠ (Round to two decimal places as needed.) What is the P-value? P-value= (Round to three decimal places as needed.) What is the conclusion about the null hypothesis? Reject the null hypothesis because the P-value is greater than the significance level, α. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. Fail to reject the null hypothesis because the…
Assume that you plan to use a significance level of a= 0.05 to test the claim that p1 = p2 . Use the given sample sizes and numbers of successes to find the P-value for the hypothesis test. n1 = 50 x1 = 8 n2 = 50 x2 = 7
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A company claims that its packages of 100 candies are distributed with the following color percentages: 15% red, 21% orange, 12% yellow, 14% brown, 24% blue, and 14% green. Use the given sample data to test the claim that the color distribution is as claimed. Use a 0.025 significance level. E Click the icon to view the color counts for the candy in the package. Click here to view the chi-square distribution table. The test statistic is (Round to two decimal places as needed.) The critical value is (Round to three decimal places as needed.) State the conclusion. Ho. There sufficient evidence to warrant rejection of the claim that the color distribution is as claimed. Candy Package Counts Candy Counts Number in Package Color Red 14 Orange 23 Yellow 10 Brown 7 Blue 27 Green 19 Enter vOur C newer in ooe
The critical value in a hypothesis test Multiple Choice depends on the value of the test statistic. is calculated from the sample data. separates the acceptance and rejection regions. usually is .05 or .01 in most statistical tests.
What is the null and alternative hypothesis for the following problem? Thank you
The October 2019 Gallup Poll reported the proportion of Republicans, Independents, and Democrats who favor the legalization of marijuana. Here are the results: Step 1: Test Set-Up Step 2. Select the Level of Significance, α A 5 percent significance level is selected. Step 3. State the Null Hypothesis (H0) and Alternate Hypothesis (H1) H0: H1: Step 4. Compose the Decision Rule Step 5. Calculate the Value of the Test Statistic, p-value, and estimate statistical power (Use G*Power) Use G*Power to calculate statistical power. Use these settings: Test family: z tests Statistical test: Proportion: Difference between two independent proportions Type of power analysis: Post hoc: Compute achieved power – given α, sample size and effect size Step 6. Decide and Report
If you use a 0.025 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 600 if you use the Z test? Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING... Question content area bottom Part 1 Which of the following decision rules is correct? A. Reject H0 if ZSTAT<−2.24 or ZSTAT>+2.24. B. Reject H0 if −2.24<ZSTAT<+2.24. C. Reject H0 if −1.96<ZSTAT<+1.96. D. Reject H0 if ZSTAT<−1.96 or ZSTAT>+1.96.
Use the random sample data to test the claim that 72% of students have internet access at home. Use 5% level of significance. Sample data: x = 158, n = 200 1. Identify the tail of the test. 2.Find the P-value 3.Will the null hypothesis be rejected? 4. Is the initial claim supported?

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