Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
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Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C):
Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)
![Standard reduction half-cell potentials at 25° C
E° (
V)
E°
Half-reaction
Half-reaction
|(V)
Au? (aq) + Зе Au('s)
1.50
Fe2 (aq) + 2e-→Fe(s)
0.45
Ag+ (aq) +e→Ag(s)
Cr3+ (aq) +e→Cr²+ (aq)
0.80
0.50
Fe+ (aq) + 3e→Fe?+ (aq) 0.77
Cr" (aq) + 3e-→Cr(s)
0.73
Cu+ (aq) + €¯→CU(s)
Zn2+
(аq) + 2е —Zn(s)
0.52
0.76
Cu2+ (aq) + 2e →Cu(s)
Mn2+ (aq) + 2e →Mn(s)
0.34
1.18
| 2H (aq) + 20→H2(g)
0.00
Al+ (aq) + 3e-→Al(s)
1.66
Fe (aq) + 3e–→Fe(s)
Mg²+ (aq) + 2e–→Mg(s)
0.036
2.37
Pb2+ (aq) + 20→P6(s)
Na+ (aq) + e¯→Na(s)
0.13
2.71
Sn²+ (aq) + 2e→Sn(s)
Ca2+ (aq) + 2e→Ca(s)
0.14
2.76
Ni?+ (aq) + 2e →Ni(s)
Bа? (аq) + 2е —Ba(s)
0.23
2.90
Co2+ (aq) + 20→C0(s)
K* (aq) +e→K(s)
0.28
2.92
Cd2+ (aq) + 2e →Cd(s)
Lit (aq) +E→Lİ(s)
0.40
3.04](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c5ef25b-bacd-4196-a26c-b8e6fa11be42%2Fe7c39b09-a857-4cd6-bbfa-b83bbe40cfcb%2Fxunjtwo_processed.png&w=3840&q=75)
Transcribed Image Text:Standard reduction half-cell potentials at 25° C
E° (
V)
E°
Half-reaction
Half-reaction
|(V)
Au? (aq) + Зе Au('s)
1.50
Fe2 (aq) + 2e-→Fe(s)
0.45
Ag+ (aq) +e→Ag(s)
Cr3+ (aq) +e→Cr²+ (aq)
0.80
0.50
Fe+ (aq) + 3e→Fe?+ (aq) 0.77
Cr" (aq) + 3e-→Cr(s)
0.73
Cu+ (aq) + €¯→CU(s)
Zn2+
(аq) + 2е —Zn(s)
0.52
0.76
Cu2+ (aq) + 2e →Cu(s)
Mn2+ (aq) + 2e →Mn(s)
0.34
1.18
| 2H (aq) + 20→H2(g)
0.00
Al+ (aq) + 3e-→Al(s)
1.66
Fe (aq) + 3e–→Fe(s)
Mg²+ (aq) + 2e–→Mg(s)
0.036
2.37
Pb2+ (aq) + 20→P6(s)
Na+ (aq) + e¯→Na(s)
0.13
2.71
Sn²+ (aq) + 2e→Sn(s)
Ca2+ (aq) + 2e→Ca(s)
0.14
2.76
Ni?+ (aq) + 2e →Ni(s)
Bа? (аq) + 2е —Ba(s)
0.23
2.90
Co2+ (aq) + 20→C0(s)
K* (aq) +e→K(s)
0.28
2.92
Cd2+ (aq) + 2e →Cd(s)
Lit (aq) +E→Lİ(s)
0.40
3.04
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