Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C): Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

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Use the tabulated electrode potentials to calculate K for the oxidation of zinc by H+ (at 25 ∘C):

Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)

Standard reduction half-cell potentials at 25° C
E° (
V)
E°
Half-reaction
Half-reaction
|(V)
Au? (aq) + Зе Au('s)
1.50
Fe2 (aq) + 2e-→Fe(s)
0.45
Ag+ (aq) +e→Ag(s)
Cr3+ (aq) +e→Cr²+ (aq)
0.80
0.50
Fe+ (aq) + 3e→Fe?+ (aq) 0.77
Cr" (aq) + 3e-→Cr(s)
0.73
Cu+ (aq) + €¯→CU(s)
Zn2+
(аq) + 2е —Zn(s)
0.52
0.76
Cu2+ (aq) + 2e →Cu(s)
Mn2+ (aq) + 2e →Mn(s)
0.34
1.18
| 2H (aq) + 20→H2(g)
0.00
Al+ (aq) + 3e-→Al(s)
1.66
Fe (aq) + 3e–→Fe(s)
Mg²+ (aq) + 2e–→Mg(s)
0.036
2.37
Pb2+ (aq) + 20→P6(s)
Na+ (aq) + e¯→Na(s)
0.13
2.71
Sn²+ (aq) + 2e→Sn(s)
Ca2+ (aq) + 2e→Ca(s)
0.14
2.76
Ni?+ (aq) + 2e →Ni(s)
Bа? (аq) + 2е —Ba(s)
0.23
2.90
Co2+ (aq) + 20→C0(s)
K* (aq) +e→K(s)
0.28
2.92
Cd2+ (aq) + 2e →Cd(s)
Lit (aq) +E→Lİ(s)
0.40
3.04
Transcribed Image Text:Standard reduction half-cell potentials at 25° C E° ( V) E° Half-reaction Half-reaction |(V) Au? (aq) + Зе Au('s) 1.50 Fe2 (aq) + 2e-→Fe(s) 0.45 Ag+ (aq) +e→Ag(s) Cr3+ (aq) +e→Cr²+ (aq) 0.80 0.50 Fe+ (aq) + 3e→Fe?+ (aq) 0.77 Cr" (aq) + 3e-→Cr(s) 0.73 Cu+ (aq) + €¯→CU(s) Zn2+ (аq) + 2е —Zn(s) 0.52 0.76 Cu2+ (aq) + 2e →Cu(s) Mn2+ (aq) + 2e →Mn(s) 0.34 1.18 | 2H (aq) + 20→H2(g) 0.00 Al+ (aq) + 3e-→Al(s) 1.66 Fe (aq) + 3e–→Fe(s) Mg²+ (aq) + 2e–→Mg(s) 0.036 2.37 Pb2+ (aq) + 20→P6(s) Na+ (aq) + e¯→Na(s) 0.13 2.71 Sn²+ (aq) + 2e→Sn(s) Ca2+ (aq) + 2e→Ca(s) 0.14 2.76 Ni?+ (aq) + 2e →Ni(s) Bа? (аq) + 2е —Ba(s) 0.23 2.90 Co2+ (aq) + 20→C0(s) K* (aq) +e→K(s) 0.28 2.92 Cd2+ (aq) + 2e →Cd(s) Lit (aq) +E→Lİ(s) 0.40 3.04
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