Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using the table.The cholesterol levels of a group of young women at a university are normally distributed, with a mean of 190 and a standard deviation of 39. What percent of the young women have thefollowing cholesterol levels? (Round your answers to one decimal place.)(a) greater than 223%(b) between 193 and 221%Need Help?Read It

Mean = mu=190Standard deviation=sigma=39Z score=(x-mu)/sigma

Answered: Use the table to answer the question.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
Find the standard deviation (rounded to the nearest unit) for the data indicated. Test Score Frequency 90 1 80 4 70 7 60 6 50 3
Calculate the standard deviation for the following set of scores: 18, 22, 26, 22, 34, 7, 18. (Use n-1 as the denominator in your calculations.) The standard deviation for this data is: Group of answer choices
for the data shown, answer the questions, round to 2 decimal places, 10.9,12.5,29.8,19.3,19.7,23.3,2.8,29.2,23.5. find the mean, median and the standard deviation.
Answer all questions: 1. What is the range and standard deviation for the following population of scores? Scores: 5,2,5,4
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table ..... CVneights = 71.2% (Round to the nearest tenth as needed.) Heights Weights 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
Electricity bills: According to a government energy agenCy 2011 was $110. 10. Assume the amounts are normally distributed with standard deviation $21.00. Use the TI-84 Plus calculator to answer the following. electricity bil in the United States in (a) Find the 7th percentile of the bill amounts. (b) Find the 58th percentile of the bill amounts. (c) Find the median of the bill amounts. Round the answers to at least two decimal places.
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. The indicated IQ score, x, is (Round to one decimal place as needed.) A 0.55 X Q
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. The indicated IQ score, x, is (Round to one decimal place as needed.)
Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using the table.A biologist found the wingspans of a group of monary butterflies to be normally distributed with a mean of 52.8 mm and a standard deviation of 2.5 mm. What percent of the butterflies had the following wingspans? (Round your answers to one decimal place.) (a) less than 48.7 mm %(b) between 50 and 55 mm %
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.506 and standard deviation o = $1.004. Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates Tax Rate Frequency 0.00–0.49 7 0.50-0.99 14 1.00–1.49 7 1.50–1.99 2.00–2.49 5 2.50–2.99 5 3.00–3.49 3.50–3.99 1 4.00-4.49 1
Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using the table.The cholesterol levels of a group of young women at a university are normally distributed, with a mean of 181 and a standard deviation of 38. What percent of the young women have the following cholesterol levels? (Round your answers to one decimal place.) (a) greater than 223 %(b) between 186 and 222 %

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