Use the table below to find the standard deviation of the following data set: Use at least three decimal places of accuracy at each step. 14, 15, 31, 32, 43, 48 X X-\bar{x} \left(X-\bar{x}\right)^2 14 15 31 32 43 48 SUM \frac{SUM}{N-1} \sqrt{\frac{SUM}{N-1}}
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Use the table below to find the standard deviation of the following data set:
Use at least three decimal places of accuracy at each step.
14, 15, 31, 32, 43, 48
X X-\bar{x} \left(X-\bar{x}\right)^2
14
15
31
32
43
48
SUM
\frac{SUM}{N-1}
\sqrt{\frac{SUM}{N-1}}
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- Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 232 feet and a standard deviation of 52 feet. We randomly sample 49 fly balls. I need help solving the problems below What's the probability that the 49 balls traveled an average of less than 224 feet? (answer must be rounded to four decimal places) Sketch the graph. Scale the horizontal axis for x̅. and shade the region corresponding to the probability Find the 70th percentile of the distribution of the average of 49 fly balls. (answer must be rounded to two decimal places) Can you please show me your work so I can understand and learn how you got the answer Thank youA set of 1100 exam scores is normally distributed with a mean = 78 and standard deviation = 4.How many students scored higher than 78? How many students scored between 74 and 82? How many students scored between 70 and 86? How many students scored between 78 and 82? How many students scored lower than 74? How many students scored lower than 82?Ana is a dedicated Skee Ball player who always rolls for the 50-point slot. The probability distribution of Ana's score X on a randomly selected roll of the ball is shown here. The mean of this probability distribution is 23.8. Score Probability 10 0.32 20 30 40 0.27 0.19 0.15 50 0.07 What is the standard deviation of X? Interpret this value. σχ 12.632. The score of a randomly selected Skee Ball roll will typically vary from the mean (23.8) by about 12.632. = ox= 159.56. The score of a randomly selected Skee Ball roll will typically vary from the mean (23.8) by about 159.56. Oox = 159.56. The score of a randomly selected Skee Ball roll will vary from the mean (23.8) by 159.56. The standard deviation cannot be calculated in this situation because we do not have a list of randomly selected Skee ball point values. x = 12.632. The score of a randomly selected Skee Ball roll will vary from the mean (23.8) by 12.632.
- In each part, use the information given to calculate the standard error of the mean. (Round your answers to one decimal place.) (a) Mean height for a sample of n = 99 women is x = 65.6 inches, and the standard deviation is s = 3.9 inches.inches(b) Mean systolic blood pressure for a sample of n = 120 men is x = 124.5, and the standard deviation is s = 7.(c) Mean systolic blood pressure for a sample of n = 360 men is x = 124.5, and the standard deviation is s = 7.Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 236 feet and a standard deviation of 44 feet. We randomly sample 49 fly balls. Part (a) If X =average distance in feet for 49 fly balls, then give the distribution of X. Round your standard deviation to two decimal places. X ____, ________,_______ ~ . Part (b) What is the probability that the 49 balls traveled an average of less than 226 feet? (Round your answer to four decimal places.)Sketch the graph. Scale the horizontal axis for X. Shade the region corresponding to the probability. Part (c) Find the 70th percentile of the distribution of the average of 49 fly balls. (Round your answer to two decimal places.) ft †of error, Claim: The standard deviation of pulse rates of adult males is more than 11 bpm. Fora random sample of 148 adult males, the pulse rates have a standard deviation of 11.6 bpm. Find the value of the test statistic. r7 *.* The value of the test statistic is (Round to two decimal places as needed.)
- OreThe graph illustrates the distribution of test scores taken by College Aigebra students. The maximum possible score on the test was 140, while the mean score was 76 and the standard deviation was 14. 34 48 62 76 90 104 Distribution of Test Scores What is the approximate percentage of students who scored between 76 and 90 on the test? What is the approximate percentage of students who scored higher than 104 on the test? What is the appraximate percentage of students who scored higher than 118 on the test? What is the approximate percentage of students who scored between 48 and 104 on the test?The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 140, while the mean score was 80 and the standard deviation was 13. + + + 41 54 67 80 93 106 119 Distribution of Test Scores What is the approximate percentage of students who scored between 54 and 106 on the test? What is the approximate percentage students who scored between 67 and 93 on the test? % What is the approximate percentage of students who scored between 80 and 93 on the test? %
- SOLVE STEP BY STEP IN DIGITAL FORMAT, DON'T USE CHATGPT A researcher in criminology is interested in determining whether the average age of offenders in a particular population has changed in recent years. The researcher collects a sample of 100 offenders and calculates that the average age of the sample is 30 years. The standard deviation of the population is known to be 5 years. The researcher wants to test whether there is evidence of a significant change in the average age of offenders, using a significance level of 0.05. Ask: What is the null hypothesis (H0) and alternative hypothesis (H1) in this study? Also, what type of statistical test would be used and what is the process for performing the test with a Z statistic? Perform the necessary calculations and put your conclusions.Now use the binomial formulas below to find the mean and standard deviation when n = 5 and p = 0.02.The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…
