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Use the summation by parts formula to derive an expression which equals the sum Hint:</> once again, it might be useful if you remember your answer to Question 1. 2K 02-1-²01 K O O O K 2K (K) K+1 n=1 2K+1(K+1) K+2 1 2n 2K+1(K+1) n+1 K 2n(n+1) - 1- - n+2 - n=1 n=1 K 2nn n+1 K K 2n(n 2) 2n n² + 3n+2

Use the summation by parts formula to derive an expression which equals the sum Hint:</> once again, it might be useful if you remember your answer to Question 1. 2K 02-1-²01 K O O O K 2K (K) K+1 n=1 2K+1(K+1) K+2 1 2n 2K+1(K+1) n+1 K 2n(n+1) - 1- - n+2 - n=1 n=1 K 2nn n+1 K K 2n(n 2) 2n n² + 3n+2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the summation by parts formula to derive an expression which equals the sum 2K -02-1-2-²01 Ο κ O Hint:</> once again, it might be useful if you remember your answer to Question 1. O O 2K (K) K+1 2K+1(K+1) K+2 K K n=1 2K+1(K+1) K+2 1 OK+1 041-2 OK!- n+1 n n+1 n=1 1. K n=1 1 K 2n(n+1) n+2 n=1 2"n n+1 K K 2K (K) 2¹ (n − 3) - n+2 n=1 K 2¹ (n-3) n+2 n=1 2n n² + 3n+2
Transcribed Image Text:Use the summation by parts formula to derive an expression which equals the sum 2K -02-1-2-²01 Ο κ O Hint:</> once again, it might be useful if you remember your answer to Question 1. O O 2K (K) K+1 2K+1(K+1) K+2 K K n=1 2K+1(K+1) K+2 1 OK+1 041-2 OK!- n+1 n n+1 n=1 1. K n=1 1 K 2n(n+1) n+2 n=1 2"n n+1 K K 2K (K) 2¹ (n − 3) - n+2 n=1 K 2¹ (n-3) n+2 n=1 2n n² + 3n+2
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