Use the sample of the greenhouse gas emissions of 32 different cars. (The amounts are in tons per year, expressed as CO2 equivalents.) Use a 0.05 significance level to test the claim that all cars have a mean greenhouse gas emission of 8.00 tons. Find the statistic, p-value and the critical value (or values).(I can ask for the satistic ,p value and critical value separately if needed)Data:CarGHGAcura RL8.7Acura TSX7.2Audi A67.7BMW 525i7.7Buick LaCrosse7.9Cadillac STS8.7Chevrolet Impala8.2Chevrolet Malibu6.8Chrysler 3009.3Dodge Charger9.3Dodge Stratus7.4Ford Crown Victoria9.3Ford Focus6.5Honda Accord6.6Hyundai Elantra6.7Infiniti M359Jaguar XJ88.6Kia Amanti9.3Kia Spectra6.5Lexus GS3007.4Lexus LS8.7Lincoln Town Car9.3Mazda 36.5Mercedes-Benz E7Mercury Grand Marquis9.3Nissan Altima7.1Pontiac G67.2Saturn Ion6.7Toyota Avalon7.2Toyota Corolla5.5Volkswagon Passat7.3Volvo S808.2 AJK1CarGHGAcura RL8.73Acura TSX7.2Greenhouse emissionsNull hypothesisAlternative hypothesis4Audi A67.7BMW 525i7.7Significance level6Buick LaCrosse7.97Cadillac STS8.7Sample mean8Chevrolet Impala8.2t-statisticChevrolet MalibuCritical value (or values)96.810Chrysler 3009.3p-value11Dodge Charger9.3Conclusion12Dodge Stratus7.4Ford Crown Vict139.314Ford Focus6.5Show any intermediate calculations around here15Honda Accord6.616Hyundai Elantra6.717Infiniti M3518Jaguar XJ88.619Kia Amanti9.320Kia Spectra6.521Lexus GS3007.422Lexus LS8.723Lincoln Town Ca9.324Mazda 36.525Mercedes-BenzMercury Grand269.327Nissan Altima7.128Pontiac G67.229Saturn lon6.730Toyota Avalon7.231Toyota Corolla5.5Volkswagon Pas327.333Volvo S808.23435

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Description: Use the sample of the greenhouse gas emissions of 32 different cars. (The amounts are in tons per year, expressed as CO2 equivalents.) Use a 0.05 significance level to test the claim that all cars have a mean greenhouse gas emission of 8.00 tons. Fin

Given: Sample size of cars (n) = 32 Hypothesized mean x¯=8 The green house emissions of all the cars…

Answered: Use the sample of the greenhouse gas…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the sample of the greenhouse gas emissions of 32 different cars. (The amounts are in tons per year, expressed as CO2 equivalents.) Use a 0.05 significance level to test the claim that all cars have a mean greenhouse gas emission of 8.00 tons. Find the statistic, p-value and the critical value (or values).

(I can ask for the satistic ,p value and critical value separately if needed)

Data:

Car	GHG
Acura RL	8.7
Acura TSX	7.2
Audi A6	7.7
BMW 525i	7.7
Buick LaCrosse	7.9
Cadillac STS	8.7
Chevrolet Impala	8.2
Chevrolet Malibu	6.8
Chrysler 300	9.3
Dodge Charger	9.3
Dodge Stratus	7.4
Ford Crown Victoria	9.3
Ford Focus	6.5
Honda Accord	6.6
Hyundai Elantra	6.7
Infiniti M35	9
Jaguar XJ8	8.6
Kia Amanti	9.3
Kia Spectra	6.5
Lexus GS300	7.4
Lexus LS	8.7
Lincoln Town Car	9.3
Mazda 3	6.5
Mercedes-Benz E	7
Mercury Grand Marquis	9.3
Nissan Altima	7.1
Pontiac G6	7.2
Saturn Ion	6.7
Toyota Avalon	7.2
Toyota Corolla	5.5
Volkswagon Passat	7.3
Volvo S80	8.2

A
J
K
1
Car
GHG
Acura RL
8.7
3
Acura TSX
7.2
Greenhouse emissions
Null hypothesis
Alternative hypothesis
4
Audi A6
7.7
BMW 525i
7.7
Significance level
6
Buick LaCrosse
7.9
7
Cadillac STS
8.7
Sample mean
8
Chevrolet Impala
8.2
t-statistic
Chevrolet Malibu
Critical value (or values)
9
6.8
10
Chrysler 300
9.3
p-value
11
Dodge Charger
9.3
Conclusion
12
Dodge Stratus
7.4
Ford Crown Vict
13
9.3
14
Ford Focus
6.5
Show any intermediate calculations around here
15
Honda Accord
6.6
16
Hyundai Elantra
6.7
17
Infiniti M35
18
Jaguar XJ8
8.6
19
Kia Amanti
9.3
20
Kia Spectra
6.5
21
Lexus GS300
7.4
22
Lexus LS
8.7
23
Lincoln Town Ca
9.3
24
Mazda 3
6.5
25
Mercedes-Benz
Mercury Grand
26
9.3
27
Nissan Altima
7.1
28
Pontiac G6
7.2
29
Saturn lon
6.7
30
Toyota Avalon
7.2
31
Toyota Corolla
5.5
Volkswagon Pas
32
7.3
33
Volvo S80
8.2
34
35

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Step 1

Given:

Sample size of cars (n) = 32

Hypothesized mean $(\bar{x}) = 8$

The green house emissions of all the cars in a sample is as follows

8.7
7.2
7.7
7.7
7.9
8.7
8.2
6.8
9.3
9.3
7.4
9.3
6.5
6.6
6.7
9
8.6
9.3
6.5
7.4
8.7
9.3
6.5
7
9.3
7.1
7.2
6.7
7.2
5.5
7.3
8.2

$α = 0.05$

Step 2

Calculating sample mean and standard deviation of GHG

$\sum x = 8.7 + 7.2 + . . . . . . . . . . . . . . . . . . + 7.3 + 8.2 = 248.8 \sum x^{2} = 8 . 7^{2} + 7 . 2^{2} + . . . . . . . . . . . . . . . . . . + 7 . 3^{2} + 8 . 2^{2} = 1970.76 S o, \bar{x} = \frac{\sum x}{n} = \frac{248.8}{32} = 7.775 s = \sqrt{\frac{1}{n - 1} \times (\sum x^{2} - n \times {\bar{x}}^{2})} = \sqrt{\frac{1}{32 - 1} \times (1970.76 - 32 \times 7 . 775^{2})} = 1.082709$

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