Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 3 4 5 Probability 0.263 0.291 0.239 0.156 0.037 0.014 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is 1.5. (Round to one decimal place as needed.) The variance is 1.2. (Round to one decimal place as needed.) The standard deviation is 1.2. (Round to one decimal place as needed.) (b) Interpret the results. The mean is , so the average batch of 1000 machine parts has The standard deviation is |. so the typical number of defects in a batch of 1000 (Round to one decimal place as needed.)

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4.1.31 Assigned Media ▼
Use the probability distribution to complete parts (a) and (b) below.
The number of defects per 1000 machine parts inspected
Defects
1
2
3
4
Probability 0.263
0.291
0.239
0.156
0.037
0.014
(a) Find the mean, variance, and standard deviation of the probability distribution.
The mean is 1.5
(Round to one decimal place as needed.)
The variance is 1.2
(Round to one decimal place as needed.)
The standard deviation is 1.2.
(Round to one decimal place as needed.)
(b) Interpret the results.
The mean is |, so the average batch of 1000 machine parts has
The standard deviation is , so the typical number of defects in a batch of 1000
(Round to one decimal place as needed.)
(1,1)
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Transcribed Image Text:Questi 4.1.31 Assigned Media ▼ Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 3 4 Probability 0.263 0.291 0.239 0.156 0.037 0.014 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is 1.5 (Round to one decimal place as needed.) The variance is 1.2 (Round to one decimal place as needed.) The standard deviation is 1.2. (Round to one decimal place as needed.) (b) Interpret the results. The mean is |, so the average batch of 1000 machine parts has The standard deviation is , so the typical number of defects in a batch of 1000 (Round to one decimal place as needed.) (1,1) More Enter your answer in the edit fields and then click Check Answer. All parts showing Clear All Check Answer 10:06 PM P Type here to search A O e . D du 2/9/2021 PriScn Hoove End VgUp 6 8.
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Step 1

Introduction:

For a discrete random variable X, taking values X = x with probability mass function (pmf) p (x), the formulae for the mean or expectation, variance, and standard deviation are:

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