Use the power reducing formulas to rewrite sin²6x cos²6x in terms of the first power of cosine. Simplify your answer as much as possible. To indicate your answer, first choose one of the four forms below. Then fill in the blanks with the appropriate numbers. sin²6x cos²6x = -cosx + cosx sin²6x cos²6x = + cosx + cosx sin 6x cos²6x = -cosx sin²6x cos²6x = + cosx 010 x 5 ?

Verify the Identity. Show ALL work. Work from Left to Right: (Start by “factoring” the L.H.S.) cos^4 theta − sin ^4 theta = 2cos^2 theta - 1

Sh 24  Advanced math    If \theta =(3\pi )/(4), find the exact value of each expression below. cos^(2)\theta

Simplify the following trigonometric expression. 1+ sin theta/ 1+csc theta Group choices A. Sin(theta) B. Sin^2 (theta) C. Tan (theta) D. Cot^2 (theta) E. Cos^2 (theta) F. 1+ cot(theta) G. 1+cos^2 (theta)

Take one step in simplifying the expression below. Evaluate the original expression and your expression at the following angles (to three decimals). Csc^2xsec^2x-csc^2x=

Multiply. Use "theta" for θ and (cos(theta))^2 for cos^2 θ. (Sin0 + Cos0)^2

explain why sine or cosine will never have a value greater than 1

Please solve

For this problem, fill in each blank with the correct answer. Syntax example: to enter r? sin (), type x^2sin(x/2) (do not use any space or * for multiplication and use parentheses for the input/argument of the sine function). To enter x? (- sin(:), type x^2(- sin(x/2)) (use parentheses when multiplying by a negative and do not use any space or * for multiplication) or just simplify to -x^2sin(x/2). It is always best to simplify your answers as much as possible. (For instance, if the answer is 2/(1/2), simplify to 4, if the answer is 2(-3) simplify to -6, if the answer is 2x(-x^2) simplify to -2x^3, etc.) Note: DO NOTI include the "dx" part in your answers below! It's already there. Evaluate the indefinite integralf x? sin ()da by following the steps outlined below. We will use the method of integration by parts which is derived from the for differentiation. We first apply integration by parts with , dv = dx du = dx, v = to get: Ja? sin(플) dz= +4/zcos (특) da. Next, we apply integration…

Use the inverse trigonometric identities to find the exact value of the expression below.sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] Select the correct choice below and fill in the answer box to complete your choice. ​(Type an exact answer. Simplify your​ answer, including any radicals. Use integers or fractions for any numbers in the​ expression.)A) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____B) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____C) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+sin^(-1)((\sqrt(3))/(2))] = _____D) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-sin^(-1)((\sqrt(3))/(2))] = _____