he expression.) A) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____ B) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____ C) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+sin^(-1)((\
he expression.) A) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____ B) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____ C) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+sin^(-1)((\
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.1: Verifying Trigonometric Identities
Problem 71E
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Use the inverse
sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))]
Select the correct choice below and fill in the answer box to complete your choice.
(Type an exact answer. Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
A) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____
B) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____
C) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+sin^(-1)((\sqrt(3))/(2))] = _____
D) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-sin^(-1)((\sqrt(3))/(2))] = _____
A) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____
B) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+(\pi -sin^(-1)((\sqrt(3))/(2)))] = _____
C) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)+sin^(-1)((\sqrt(3))/(2))] = _____
D) sin[(2\pi )/(3)-sin^(-1)(-(\sqrt(3))/(2))] = sin[(2\pi )/(3)-sin^(-1)((\sqrt(3))/(2))] = _____
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