Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5 % significance level. Test Ho: p = 0.5 vs Ha: p > 0.5 using the sample results p 0.60 with n = 75 Round your answer for the test statistic to two decimal places, and your answer for the p-value to three decimal places. test statistic = p-value =i Conclusion: v Ho- Attempts: 0 of 1 used Submit Answer Save for Later

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### Hypothesis Testing Using Normal Distribution

**Current Attempt in Progress**

Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5% significance level.

#### Problem Statement:
Test \( H_0 : p = 0.5 \) vs \( H_a : p > 0.5 \) using the sample results \( \hat{p} = 0.60 \) with \( n = 75 \).

### Instructions:

1. **Calculate the Test Statistic:**
    - Use the formula for the test statistic for proportions:
      \[
      z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}}
      \]
      where \( \hat{p} \) is the sample proportion, \( p_0 \) is the hypothesized population proportion, and \( n \) is the sample size.

2. **Calculate the p-value:**
    - Use the standard normal (Z) table to find the p-value corresponding to the calculated test statistic.
    - Ensure to round your answer for the test statistic to two decimal places and the p-value to three decimal places.

3. **State the Conclusion:**
    - Based on the p-value, conclude whether to reject the null hypothesis \( H_0 \) or fail to reject the null hypothesis. Use a significance level of \( \alpha = 0.05 \).

### Example Inputs:
- test statistic: [Input box]
- p-value: [Input box]
- Conclusion: [Dropdown menu - Options for decision]
  - \( H_0 \) (Fail to reject the null hypothesis)
  - \( H_a \) (Reject the null hypothesis)

### Action:
- **Save for Later:** [Button to save progress]
- **Submit Answer:** [Button to submit the answer]

Attempts: 0 of 1 used

*Note: This exercise helps in understanding the process of hypothesis testing and applying the normal distribution to test population proportions.*
Transcribed Image Text:### Hypothesis Testing Using Normal Distribution **Current Attempt in Progress** Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5% significance level. #### Problem Statement: Test \( H_0 : p = 0.5 \) vs \( H_a : p > 0.5 \) using the sample results \( \hat{p} = 0.60 \) with \( n = 75 \). ### Instructions: 1. **Calculate the Test Statistic:** - Use the formula for the test statistic for proportions: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}} \] where \( \hat{p} \) is the sample proportion, \( p_0 \) is the hypothesized population proportion, and \( n \) is the sample size. 2. **Calculate the p-value:** - Use the standard normal (Z) table to find the p-value corresponding to the calculated test statistic. - Ensure to round your answer for the test statistic to two decimal places and the p-value to three decimal places. 3. **State the Conclusion:** - Based on the p-value, conclude whether to reject the null hypothesis \( H_0 \) or fail to reject the null hypothesis. Use a significance level of \( \alpha = 0.05 \). ### Example Inputs: - test statistic: [Input box] - p-value: [Input box] - Conclusion: [Dropdown menu - Options for decision] - \( H_0 \) (Fail to reject the null hypothesis) - \( H_a \) (Reject the null hypothesis) ### Action: - **Save for Later:** [Button to save progress] - **Submit Answer:** [Button to submit the answer] Attempts: 0 of 1 used *Note: This exercise helps in understanding the process of hypothesis testing and applying the normal distribution to test population proportions.*
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