Answered: Use the mysql command to log into the…

Use the mysql command to log into the server01 MySQL host with the username tom, password P@$$w0rd! and run the script insert.sql.

Programming with Microsoft Visual Basic 2017

8th Edition

ISBN:9781337102124

Author:Diane Zak

Publisher:Diane Zak

Chapter11: Sql Server Databases

Section: Chapter Questions

Problem 11RQ

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Use SQL to insert the values NULL, prod1, and $9.99 into the PRODUCTS table Use the mysql command to log into the server01 MySQL host with the username tom, password P@$$w0rd! and run the script insert.sql. Use SQL to select the name and city columns from the Customers table. Select all rows from the Orders table where the CustomerID is greater than 300. Select all rows from the Orders table where the CustomerID is 400 or 500.
Consider the following command: UPDATE customerSET customer_id = customer_id --1; What happens if we run this command in MySQL? The customer_id in the customer table for all records is incremented by 1. The customer table has every customer_id set to the same value as it previously had. An error is thrown due to the --. The customer_id in the customer table for all records is decremented by 1.
Use Oracle to create this PL/SQL command : Perform Exception handling and use oracle error table that will be raised if the user entered. If the user tried to update shopper email. Refer to bb_shopper table Test your script and raise the exception.
Which of the following is a correct statement? a. A commit is issued implicitly when a user exits SQL Developer or SQLPlus. b. A commit is issued implicitly when a DDL command is executed. c. A commit is issued automatically when a DML command is executed. d. All of the above are correct. e. Both a and b are correct. f. Both a and c are correct.
Which of the following statements deletes all rows in the HOMEWORK10 table? a. DELETE FROM homework10; b. DELETE . FROM homework10; c. DELETE FROM homework10; d. DELETE FROM homework10 WHERE amid = ; e. Both c and d delete all rows in the HOMEWORK10 table.
plz help with the following: Change the following commands to oracle commands line meaning that they would be able to create the tables and their relationships when used on oracle live sql or oracle sql developper, CREATE TABLE `book`( `num` INT(20) NOT NULL AUTO_INCREMENT, `title` VARCHAR(20), `year` DATE, `subject` VARCHAR(20), `checkedout` DATETIME, `checkedin` DATETIME, PRIMARY KEY (`num`) ); CREATE TABLE `client`( `CID` INT(20) NOT NULL AUTO_INCREMENT, `fname` VARCHAR(25), `lname` VARCHAR(25), `type` VARCHAR(25), `num` INT(20), PRIMARY KEY (`CID`), FOREIGN KEY (`num`) REFERENCES `emp`.`state`(`state_id`) ); CREATE TABLE `author`( `id` INT(10) NOT NULL AUTO_INCREMENT, `year` DATE, `fName` VARCHAR(20), `lname` VARCHAR(20), `num` INT(20), PRIMARY KEY (`id`) ); ALTER TABLE `author` ADD FOREIGN KEY (`num`) REFERENCES `book`(`num`); ALTER TABLE `client` ADD CONSTRAINT `client_ibfk_1` FOREIGN KEY (`num`) REFERENCES `book`(`num`);
Write and execute the command to retrieve the customer ID, first name, and last name of each customer in the MAJOR_CUSTOMER VIEW with a balance that exceeds the credit limit.
1- Create a SQL statement to Change the CONTACT of SID 1523 to 95472891 in CLIENTS table. 2- Create a SQL statement to Display the RID, RType and a new column that will divide RATE to the BEDROOM column in the ROOMS table. Use the alias "Rate per Room". help
write and execute the command to retrieve the reservation id, trip id, trip date, and customer last name for every reservation in the reservation _ customer view with a trip date of September 11,2016.
Which of the following is a valid SQL statement? ( refer to the tables in the JustLee Books database). a. CREATE TABLE tablel (col1 NUMBER PRIMARY KEY, col2 VARCHAR2(20) PRIMARY KEY, col3 DATE DEFAULT SYSDATE, col4 VARCHAR2(2)); b. CREATE TABLE tablel (col1 NUMBER PRIMARY KEY, col2 VARCHAR2(20), col3 DATE, col4 VARCHAR2 (2) NOT NULL, CONSTRAINT tablel_col3_ck CHECK (col3=SYSDATE)); c. CREATE TABLE tablel (col1 NUMBER, col2 VARCHAR2(20), col3 DATE, col4 VARCHAR2(2), PRIMARY KEY (coll)); d. CREATE TABLE tablel (coll NUMBER, col2 VARCHAR2(20), col3 DATE DEFAULT SYSDATE, col4 VARCHAR2(2);
Beta MySQL Main.sql X HN34567 2 7 ); @paiza.io MySQL Online CREATE TABLE BOOK_STORES ( Store_ID NUMBER(8) NOT NULL, Name VARCHAR2(30) UNIQUE NOT NULL, Contact VARCHAR2(30), Rep_ID VARCHAR2(5), PRIMARY KEY(Store_ID) Run (Ctrl-Enter) Enter a title here New code Name VARCHAR2(30) UNIQUE NOT NULL, Contact VARCHAR2 (30),' at line 2 Recent code WebDev Runtime error(Exit status:1) English ▼ Sign Up Sign In (1.38 sec) Output Runtime error Input Comments 0 ERROR 1064 (42000) at line 2: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'NUMBER (8) NOT NU LL,
PLZ help with the following: Make a discount of 10% for all paintings. Write the SQL command to save all the changes made to the table. Remove a gallery number ‘5’ from the GALLERY table. Is deleting a GALLERY row creates sql file CREATE TABLE GALLERY (GAL_NUM char(4),GAL_OWNER varchar(35),GAL_AREACODE char(3),GAL_PHONE char(8),GAL_RATE number);INSERT INTO GALLERY VALUES('5','L. R. Gilliam','901','123-4456',0.37);INSERT INTO GALLERY VALUES('6','G. G. Waters','405','353-2243',0.45 );INSERT INTO GALLERY VALUES('1','N. D. Cosner','203','123-9956',0.67);INSERT INTO GALLERY VALUES('2','S. H. Artwork','415','154-3243',0.30); /* -- */ CREATE TABLE PAINTER (PTR_NUM char(4),PTR_LASTNAME varchar(15) NOT NULL,PTR_FIRSTNAME varchar(15) NOT NULL,PTR_AREACODE char(3),PTR_PHONE char(8));INSERT INTO PAINTER VALUES('123','Ross','Georgette','901','885-4567');INSERT INTO PAINTER VALUES('126','Itero','Julio','901','346-1112');INSERT INTO PAINTER VALUES('127','Geoff','George','615','221-4456');…